Question

我在SQL Server Management Studio 2005中运行了一个SQL查询，当我的Total_Cost列的结果没有按照我想要的格式化时。

我尝试添加一个Declare @TOTAL_COST decimal(12,2)条款，但似乎无法使其工作，所以再次将其删除。

我的查询是： -

SELECT     
   vwREP_GP_ContractProjectPurchaseCostCatID.PACOSTCATID AS COST_CAT_CODE, 
   vwREP_GP_ContractProjectPurchaseCostCatID.PACOSTCATNME AS COST_CAT_NAME, 
   vwREP_GP_ContractProjectPurchaseRpt.COST, 
   vwREP_GP_ContractProjectPurchaseRpt.ITEMDESC AS ITEM, 
   vwREP_GP_ContractProjectPurchaseRpt.CREDITOR, 
   vwREP_GP_ContractProjectPurchaseRpt.DOC_NUM AS DOCUMENT_NUMBER, 
   vwREP_GP_ContractProjectPurchaseRpt.DESCRIPTION, 
   vwREP_GP_ContractProjectPurchaseRpt.DOC_DATE AS DATE,  
   vwREP_GP_ContractProjectPurchaseRpt.PROJECT AS JOB_CODE_STAGE, 
   vwREP_GP_ContractProjectPurchaseRpt.COMPOUNDNAME AS CATEGORY_DESCRIPTION
FROM         
   vwREP_GP_ContractProjectPurchaseCostCatID 
INNER JOIN
   vwREP_GP_ContractProjectPurchaseRpt ON vwREP_GP_ContractProjectPurchaseCostCatID.PACOSTCATID = vwREP_GP_ContractProjectPurchaseRpt.PACOSTCATID

SELECT  
   CATEGORY_DESCRIPTION, SUM(COST) AS TOTAL_COST 
FROM    
   (SELECT 
        COMPOUNDNAME AS CATEGORY_DESCRIPTION, COST 
    FROM   
        vwREP_GP_ContractProjectPurchaseRpt 
   ) A
GROUP BY 
    CATEGORY_DESCRIPTION

这给了我正在寻找的结果，但Total_Cost以5十进制格式生成数字。

例如：

156713.55000

获得结果的最佳方法是什么 -

156713.55

提前致谢

Answer 1

SELECT     vwREP_GP_ContractProjectPurchaseCostCatID.PACOSTCATID AS COST_CAT_CODE, 
           vwREP_GP_ContractProjectPurchaseCostCatID.PACOSTCATNME AS COST_CAT_NAME, 
           vwREP_GP_ContractProjectPurchaseRpt.COST, 
           vwREP_GP_ContractProjectPurchaseRpt.ITEMDESC AS ITEM, 
           vwREP_GP_ContractProjectPurchaseRpt.CREDITOR, 
           vwREP_GP_ContractProjectPurchaseRpt.DOC_NUM AS DOCUMENT_NUMBER, 
           vwREP_GP_ContractProjectPurchaseRpt.DESCRIPTION, 
           vwREP_GP_ContractProjectPurchaseRpt.DOC_DATE AS DATE,  
           vwREP_GP_ContractProjectPurchaseRpt.PROJECT AS JOB_CODE_STAGE, 
           vwREP_GP_ContractProjectPurchaseRpt.COMPOUNDNAME AS CATEGORY_DESCRIPTION


FROM         vwREP_GP_ContractProjectPurchaseCostCatID INNER JOIN
                      vwREP_GP_ContractProjectPurchaseRpt ON vwREP_GP_ContractProjectPurchaseCostCatID.PACOSTCATID = vwREP_GP_ContractProjectPurchaseRpt.PACOSTCATID



SELECT  CATEGORY_DESCRIPTION, CAST(SUM(COST) AS DECIMAL(12, 2)) AS TOTAL_COST

FROM    (  
        SELECT COMPOUNDNAME AS CATEGORY_DESCRIPTION, COST 
        FROM   vwREP_GP_ContractProjectPurchaseRpt 
        ) A
GROUP BY 
        CATEGORY_DESCRIPTION

Answer 2

如果你只存储2个小数位，那我就不用担心了。我所知道的几乎所有语言都会丢掉额外的零（SQL除外）：）

另一方面，如果你存储超过2位小数（即123.456），那么我会使用round（）代替准确度。

 ...

SELECT  CATEGORY_DESCRIPTION, round(SUM(COST), 2) AS TOTAL_COST  

FROM    (   
        SELECT COMPOUNDNAME AS CATEGORY_DESCRIPTION, COST  
        FROM   vwREP_GP_ContractProjectPurchaseRpt  
        ) A 

GROUP BY  
        CATEGORY_DESCRIPTION

SQL小数问题

2 个答案: