我正在尝试查找来电号码的信息,如运营商,号码位置,Pincode。请帮忙。
答案 0 :(得分:0)
对不起它在android中是不可能的。
答案 1 :(得分:0)
<receiver android:name=".CustomBroadcastReceiver">
<intent-filter>
<action android:name="android.intent.action.PHONE_STATE" />
</intent-filter>
</receiver>
</application>
<uses-sdk android:minSdkVersion="5" />
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.WRITE_CONTACTS" />
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
public class CustomPhoneStateListener extends PhoneStateListener {
private static final String TAG = "CustomPhoneStateListener";
public void onCallStateChange(int state, String incomingNumber){
Log.v(TAG, "WE ARE INSIDE!!!!!!!!!!!");
Log.v(TAG, incomingNumber);
switch(state){
case TelephonyManager.CALL_STATE_RINGING:
Log.d(TAG, "RINGING");
break;
}
}
public class CustomBroadcastReceiver extends BroadcastReceiver {
private static final String TAG = "CustomBroadcastReceiver";
@Override
public void onReceive(Context context, Intent intent) {
Log.v(TAG, "WE ARE INSIDE!!!!!!!!!!!");
TelephonyManager telephony = (TelephonyManager)context.getSystemService(Context.TELEPHONY_SERVICE);
CustomPhoneStateListener customPhoneListener = new CustomPhoneStateListener();
telephony.listen(customPhoneListener, PhoneStateListener.LISTEN_CALL_STATE);
Bundle bundle = intent.getExtras();
String phoneNr= bundle.getString("incoming_number");
Log.v(TAG, "phoneNr: "+phoneNr);
}
这可能是你想要的
答案 2 :(得分:0)
TelephonyManager telephonyManager =((TelephonyManager) Context.getSystemService(Context.TELEPHONY_SERVICE));
String operatorName = telephonyManager.getNetworkOperatorName();
similarly the sim operator can be retrieved by using:
String operatorName = telephonyManager.getSimOperatorName();