我需要将Android设备中的一些数据发送到我的服务器。我通过JSON这样做。我在Android上实现了JSON帖子,我正在尝试在服务器端进行映射以检索该数据。我的问题是我不断得到一个空字符串。
用于发送JSON的Android方法:
private void sendJson(final String json, final String URL) {
Thread t = new Thread(){
public void run() {
Looper.prepare(); //For Preparing Message Pool for the child Thread
HttpClient client = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); //Timeout Limit
try{
HttpPost post = new HttpPost(URL);
StringEntity se = new StringEntity(json);
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
post.setEntity(se);
client.execute(post);
}
catch(Exception e){
e.printStackTrace();
}
Looper.loop(); //Loop in the message queue
}
};
t.start();
}
服务器端方法:
@RequestMapping(value = "/getLatestCalls", method = RequestMethod.POST)
public void getData(@ModelAttribute String json){
//... do something
}
问题在于,在这种方法中,我的 json String每次都是“”。我也尝试过使用@RequestParam
但是它不再进入方法了。我也试过了@ModelAttribute("json")
。
有人可以在这里开导一下吗?提前谢谢。
答案 0 :(得分:2)
这是解决方案,它运行正常。
@Controller
public class DataCollector {
@RequestMapping(value = "/clientdatacollector", method = RequestMethod.POST)
public @ResponseBody
void abc(Writer writer, @RequestParam("gpsdata") String gpsJSON) {
try {
// here is your jsonstring ;)
writer.write(gpsJSON.toString());
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
客户端
public static void httptest() {
ArrayList<TravellingData> tdArray = new ArrayList<TravellingData>();
Gson gson = new Gson();
String jsonString = "";
for (int i = 0; i < 1; i++) {
tdArray.add(ObjectCreater.createMockTravellingDataObject());
}
jsonString = gson.toJson(tdArray);
HttpClient client = new DefaultHttpClient();
HttpPost post = null;
try {
post = new HttpPost(
"http://localhost:8080/uygulama/clientdatacollector");
} catch (URISyntaxException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
nameValuePairs.add(new BasicNameValuePair("gpsdata", jsonString));
post.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = null;
try {
response = client.execute(post);
} catch (HttpException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
BufferedReader rd = new BufferedReader(new InputStreamReader(
response.getEntity().getContent()));
String line = "";
while ((line = rd.readLine()) != null) {
System.out.println(line);
}
} catch (IOException e) {
e.printStackTrace();
}
}
答案 1 :(得分:0)
尝试使用@RequestBody。它应该工作。