如何使用javapns从apple的增强通知格式获取错误响应数据包

时间:2012-05-17 14:02:42

标签: java ios apple-push-notifications

ResponsePacket theErrorResponse = pushingNotification.getResponse();我正在使用javapns2.2并试图从apple的增强通知格式中捕获错误响应数据包。当我发送推送通知(例如,使用无效令牌)时代码

Exception theProblem = pushedNotification.getException();
theProblem.printStackTrace();

向控制台输出一些错误,但

ResponsePacket theErrorResponse = pushedNotification.getResponse();
if (theErrorResponse != null && theErrorResponse.isErrorResponsePacket()) {
      System.out.println(theErrorResponse.getMessage());
      System.out.println(theErrorResponse.getStatus());
}

始终返回 null。如何使用getResponse()获取状态代码?

以下是我的代码的一部分:

List<PushedNotification> notifications = Push.payload(payload, keystore, password, production, devices);

        for (PushedNotification pushedNotification : notifications) {
            if(pushedNotification.isSuccessful())
            {
                System.out.println(pushedNotification.getDevice().getToken());                  
            }
            else
            {
                System.out.println(pushedNotification.getDevice().getToken());

                Exception theProblem = pushedNotification.getException();
                theProblem.printStackTrace();

                ResponsePacket theErrorResponse = pushedNotification.getResponse();
                if (theErrorResponse != null && theErrorResponse.isErrorResponsePacket()) {
                        System.out.println(theErrorResponse.getMessage());
                        System.out.println(theErrorResponse.getStatus());
                }

            }
        }

感谢您的帮助

1 个答案:

答案 0 :(得分:1)

我明白了。

getResponse()返回null,因为异常机制阻止对APN的调用更有效。真正的错误包含在异常机制中。

在此链接中,所有内容均为超级解释: http://code.google.com/p/javapns/issues/detail?id=79&can=1