我编写了一个从互联网上下载一些数据的代码。比我想把它变成asyncTask。之后,下载停止了工作。它似乎无法完成try {}部分所以跳过exept。
从主活动“Nekaj”我调用loadData()类,它扩展了AsyncData。从那里我在try命令中调用“oto”类。 “oto”类用于从Internet读取内容并返回字符串数组。当我直接从“Nekaj”类调用oto类时,这个工作。使用AsyncTask我做错了什么? 这是代码:
public class Nekaj extends Activity {
TextView Tkolo, Tbroj1;
String[] brojevi_varijabla;
String privremena_varijabla = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.bez_provjere_739);
Tkolo = (TextView) findViewById(R.id.Xkolo);
Tbroj1 = (TextView) findViewById(R.id.Xbroj1);
/*
* try { privremena_varijabla = test.kolo_739();
* Tkolo.setText(privremena_varijabla); } catch (Exception e) { // TODO
* Auto-generated catch block e.printStackTrace(); }
*/
new loadData().execute();
}
public class loadData extends AsyncTask<String, Integer, String> {
@Override
protected String doInBackground(String... arg0) {
// TODO Auto-generated method stub
Oto test = new Oto();
try {
brojevi_varijabla = test.brojevi_739();
if (Integer.valueOf(brojevi_varijabla[0]) > 10) {
Tbroj1.setText("" + brojevi_varijabla[0]);
} else {
Tbroj1.setText(" " + brojevi_varijabla[0]);
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
}
public class Oto {
public String[] brojevi_739() throws Exception {
int i = 0;
int uvjet = 0;
int varijabla = 0;
char[] znak = { '>', '<' };
BufferedReader in = null;
String data[] = null;
String provjera = "date-info";
int[] polje = new int[2];
try {
HttpClient klijent = new DefaultHttpClient();
URI webstranica = new URI(
"https://www.aaa.bb");
HttpGet zahtjev = new HttpGet();
zahtjev.setURI(webstranica);
HttpResponse odgovor = klijent.execute(zahtjev);
in = new BufferedReader(new InputStreamReader(odgovor
.getEntity().getContent()));
StringBuffer brojevi = new StringBuffer("");
String brojevi_string = null;
String neki_string = null;
String red = "";
in.skip(21000);
while ((red = in.readLine()) != null) {
varijabla = red.indexOf(provjera);
if (varijabla != -1) {
// 1. KOLO
if (uvjet == 0) { // onda sadrži taj
// substring
// !!!!
red = in.readLine(); // sada string red sadrži ono
// što
// želim, još moram samo to
// izrezati!!
do {
if (i == 0) {
varijabla = red.indexOf(znak[i]);
}
else {
varijabla = red.indexOf(znak[i], polje[0]);
}
if (varijabla != -1) // ako taj znak postoji u
// stringu
{
if (i == 0) {
polje[i] = varijabla + 1;
}
else {
polje[i] = varijabla;
}
i++;
}
} while (i <= 1);
neki_string = red.substring(polje[0], polje[1]);
Tkolo.setText(neki_string);
provjera = "Dobitna kombinacija";
uvjet++;
continue;
}
}
}
in.close();
brojevi_string = brojevi.toString();
data = brojevi_string.split("\n");
return data;
} finally {
if (in != null) {
try {
in.close();
return data;
} catch (Exception e) {
e.printStackTrace();
}
}
}
}
}}
答案 0 :(得分:1)
实际上,您正在尝试更新 AsyncTask 的doInBackGround()
中的UI,因此不允许(doInBack ..在非UI线程中运行..),因此请更新UI AsyncTask 的onPostExecute()
中的代码..
试试这个,让我知道发生了什么......
public class loadData extends AsyncTask<String, Integer, String> {
@Override
protected String doInBackground(String... arg0) {
// TODO Auto-generated method stub
Oto test = new Oto();
try {
brojevi_varijabla = test.brojevi_739();
if(brojevi_varijabla != null)
return brojevi_varijabla[0];
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result)
{
if(result != null)
{
if (Integer.valueOf(result) > 10) {
Tbroj1.setText("" + result;
} else {
Tbroj1.setText(" " + result);
}
}
}
}
答案 1 :(得分:1)
你做错了是doInBackground()方法中的Tbroj1.setText()。您需要做的是使用onPostExecute方法在UI上发布您的数据:
public class loadData extends AsyncTask<String, Integer, Boolean> {
protected Long doInBackground(String... arg0) {
Oto test = new Oto();
Boolean result = false;
try {
brojevi_varijabla = test.brojevi_739();
result = true;
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return result;
}
protected void onPostExecute(Boolean result) {
if(result){
if (Integer.valueOf(brojevi_varijabla[0]) > 10) {
Tbroj1.setText("" + brojevi_varijabla[0]);
} else {
Tbroj1.setText(" " + brojevi_varijabla[0]);
}
}
}
}
答案 2 :(得分:0)
使用onPostExecute(Void result1){}
捕获结果并执行那里所需的操作
答案 3 :(得分:0)
您无法直接在非UI(后台)线程上操作UI元素,这是doInBackground()
始终运行的位置。使用AsyncTask
的常用方法是获取doInBackground()
中的数据,将其作为值返回,然后在onPostExecute()
中处理UI更改。例如:
public class loadData extends AsyncTask<String, Integer, String> {
@Override
protected String doInBackground(String... arg0) {
Oto test = new Oto();
try {
brojevi_varijabla = test.brojevi_739();
if (Integer.valueOf(brojevi_varijabla[0]) > 10) {
return "" + brojevi_varijabla[0];
} else {
return " " + brojevi_varijabla[0];
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
if (result != null) Tbroj1.setText(result);
}
}