Spring,JPA事务仅在JUnit测试中起作用,但在应用程序中不起作用

时间:2012-05-17 09:43:47

标签: spring web-applications transactions junit spring-data-jpa

我的交易有点问题。我使用Spring 3.1.1.RELEASE,Spring Data 1.0.3.RELEASE JPA和Hibernate提供程序。当我开始一个junit测试时,用@Transactional注释的方法看起来很好但是当我启动整个应用程序时没有错误但是事务不起作用。 这是我的配置和示例代码:

的applicationContext.xml

<context:annotation-config />
    <context:component-scan base-package="com.sheedo.upload" />
    <jpa:repositories base-package="com.sheedo.upload.repository" />
    <tx:annotation-driven transaction-manager="transactionManager" />

    <bean
        class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
        <property name="locations">
            <list>
                <value>classpath*:messages/*.properties</value>
                <value>classpath*:*.properties</value>
            </list>
        </property>
    </bean>

    <bean id="entityManagerFactory"
        class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="persistenceUnitName" value="persistenceUnit" />
        <property name="dataSource" ref="dataSource" />
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory" />
    </bean>

    <bean id="dataSource" class="com.mysql.jdbc.jdbc2.optional.MysqlDataSource">
        <property name="url" value="${jdbc.url}" />
        <property name="user" value="${jdbc.username}" />
        <property name="password" value="${jdbc.password}" />
    </bean>

的persistence.xml

<persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL">
    <provider>org.hibernate.ejb.HibernatePersistence</provider>
    <properties>
        <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLInnoDBDialect" />
        <property name="hibernate.hbm2ddl.auto" value="update" />
        <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.ImprovedNamingStrategy" />
        <property name="hibernate.connection.charSet" value="UTF-8" />
        <property name="hibernate.show_sql" value="true" />
    </properties>
</persistence-unit>

UserRepository.java

  

public interface UserRepository扩展了CrudRepository&lt; User,Long&gt; {}

UserServiceImpl.java

@Service("userService")
public class UserServiceImpl implements UserService {

    @Autowired
    private UserRepository userRepository;

    @Override
    @Transactional
    public void addUser(String name, String surname) {
        User u = new User(name, surname);
        userRepository.save(u);
        throw new RuntimeException(); // to invoke a rollback
    }
}

UserServiceTest.java

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = { "classpath:/META-INF/spring/root-context.xml" })
public class UserServiceTest {

    Logger log = LoggerFactory.getLogger(getClass());

    @Autowired
    private UserService userService;

    @Test
    public void testUserAdd() {
        userService.addUser("John", "Doe");
    }

}

在这种JUnit测试的情况下,虽然服务方法使用@Transactional注释,但事务不起作用。当我将这个注释添加到testUserAdd()方法时,我在控制台中得到了这个:

2012-05-17 11:17:54,208 INFO [org.springframework.test.context.transaction.TransactionalTestExecutionListener] - Rolled back transaction after test execution for test context [[TestContext@23ae2a testClass = UserRepositoryTest, testInstance = com.sheedo.upload.repository.UserRepositoryTest@7f52c1, testMethod = testUserAdd@UserRepositoryTest, testException = java.lang.RuntimeException, mergedContextConfiguration = [MergedContextConfiguration@111fd28 testClass = UserRepositoryTest, locations = '{classpath:/META-INF/spring/root-context.xml}', classes = '{}', activeProfiles = '{}', contextLoader = 'org.springframework.test.context.support.DelegatingSmartContextLoader']]]

我认为这是正确的。那么,@Transactional注释怎么可能只在Junit测试类中起作用,而在其他的spring bean中却不行呢?

我的理论是SpringJUnit4ClassRunner以某种方式提供了此交易。我的弹簧配置中有什么问题导致交易在我的应用程序中不起作用但仅在Junit测试类中有效吗? appContext中缺少什么东西?

编辑: 日志:

2012-05-17 12:46:10,770 DEBUG [org.springframework.orm.jpa.JpaTransactionManager] - Creating new transaction with name [org.springframework.data.jpa.repository.support.SimpleJpaRepository.save]: PROPAGATION_REQUIRED,ISOLATION_DEFAULT; ''
2012-05-17 12:46:10,770 DEBUG [org.springframework.orm.jpa.JpaTransactionManager] - Opened new EntityManager [org.hibernate.ejb.EntityManagerImpl@e4080] for JPA transaction
2012-05-17 12:46:10,979 DEBUG [org.springframework.orm.jpa.JpaTransactionManager] - Not exposing JPA transaction [org.hibernate.ejb.EntityManagerImpl@e4080] as JDBC transaction because JpaDialect [org.springframework.orm.jpa.DefaultJpaDialect@1f87491] does not support JDBC Connection retrieval
Hibernate: insert into user (name, surname) values (?, ?)
2012-05-17 12:46:11,062 DEBUG [org.springframework.orm.jpa.JpaTransactionManager] - Initiating transaction commit
2012-05-17 12:46:11,062 DEBUG [org.springframework.orm.jpa.JpaTransactionManager] - Committing JPA transaction on EntityManager [org.hibernate.ejb.EntityManagerImpl@e4080]
2012-05-17 12:46:11,142 DEBUG [org.springframework.orm.jpa.JpaTransactionManager] - Closing JPA EntityManager [org.hibernate.ejb.EntityManagerImpl@e4080] after transaction
2012-05-17 12:46:11,142 DEBUG [org.springframework.orm.jpa.EntityManagerFactoryUtils] - Closing JPA EntityManager

1 个答案:

答案 0 :(得分:2)

我有完全相同的问题。另外,请阅读在我的网络配置中添加<tx:annotation-driven/>标记的解决方案(spring-servlet.xml,而不是applicationContext.xml),并为我工作。

但我不认为这是一个好的解决方案,所以我试着理解为什么会这样......

而且,事实证明,我<context:component-scan>中的spring-servlet.xml标记在其扫描中也包含@Service类(base-package规范过于笼统)。这很奇怪,因为我有一个include-filter来引用@Controller注释......但无论如何,似乎Web层的应用程序上下文是创建@Service实例的应用程序上下文而不是为applicationContext.xml创建的应用程序上下文 - 这是定义业务层的应用程序上下文 - 并且由于前者没有启用事务性...我没有任何交易。

解决方案(好的):component-scan的更好(更具体)spring-servlet.xml配置