希望我说得对...
我怎样才能找到ID = 68的索引?
我需要帮助创建一个能够返回索引2的函数...谢谢!
$posts = Array (
[0] => stdClass Object
(
[ID] => 20
[post_author] => 1
[post_content] =>
[post_title] => Carol Anshaw
)
[1] => stdClass Object
(
[ID] => 21
[post_author] => 1
[post_content] =>
[post_title] => Marie Arana
)
[2] => stdClass Object
(
[ID] => 68
[post_author] => 1
[post_content] =>
[post_title] => T.C. Boyle
)
[3] => stdClass Object
(
[ID] => 1395
[post_author] => 1
[post_content] =>
[post_title] => Rosellen Brown
)
)
答案 0 :(得分:4)
制作一个简单的函数,遍历数组
封装而不是让它挂起
在粘贴社区的数据结构时,请记住使用var_export 而不是print_r
你可以做出如此微不足道的功能:
function getKeyForId($id, $haystack) {
foreach($haystack as $key => $value) {
if ($value->ID == $id) {
return $key;
}
}
}
$keyFor68 = getKeyForId(68, $posts);
但是将特定功能挂起是没有意义的。你可以这样使用ArrayObject:
class Posts extends ArrayObject {
public function getKeyForId($id) {
foreach($this as $key => $value) {
if ($value->ID == $id) {
return $key;
}
}
}
}
使用示例:
$posts = new Posts();
$posts[] = new StdClass();
$posts[0]->ID = 1;
$posts[0]->post_title = 'foo';
$posts[] = new StdClass();
$posts[1]->ID = 68;
$posts[1]->post_title = 'bar';
$posts[] = new StdClass();
$posts[2]->ID = 123;
$posts[2]->post_title = 'test';
echo "key for post 68: ";
echo $posts->getKeyForId(68);
echo "\n";
var_export($posts[$posts->getKeyForId(68)]);
输出:
key for post 68: 1
stdClass::__set_state(array(
'ID' => 68,
'post_title' => 'bar',
))
答案 1 :(得分:0)
function findIndexById($id, $array) {
foreach($array as $key => $value) {
if($value->ID == $id) {
return $key;
}
}
return false;
}
并且您可以像findIndexById(68, $array);
一样搜索它,如果它发现错误,它将返回数组的索引。