Question

我有以下字典：

# a small DB of people who stole my books

dic = {
'Cohen'     : 'Calvino' 'Evertt' 'Borges',
'Larry'     : 'The Bible', 
'Volanski'  : 'Phone Book'
}

# here's an abortive attempt to print it in a CSV format
for k in dic.keys():
    print (k, '\t')
for v in dic.keys():
    print (dic[v], ' ')

这是丑陋的输出：

Volanski    
Phone Book  
CalvinoEverttBorges  
The Bible  
Cohen   
Phone Book  
CalvinoEverttBorges  
The Bible  
Larry   
Phone Book  
CalvinoEverttBorges  
The Bible

我希望输出看起来像这样：

Cohen      Larry       Volanski  
Calvino    The Bible   Phone Book  
Evertt  
Borgest

（只有标签分隔，我没有设法在这里显示）

Answer 1

dic = {
   'Cohen'     : ['Calvino', 'Evertt', 'Borges'],
   'Larry'     : ['The Bible'],
   'Volanski'  : ['Phone Book']
}


ordered = []
maxlen = 0

for k in sorted(dic.keys()):
    lst = [k] + dic[k]
    maxlen = max(len(lst), maxlen)
    ordered.append(iter(lst))

for i in range(maxlen):
    print "\t".join(next(j, '') for j in ordered)

Answer 2

您可以制作整洁的格式

dic = {'Cohen'     : ['Calvino', 'Evertt', 'Borges'],
       'Larry'     : ['The Bible'],
       'Volanski'  : ['Phone Book']}

# Get max name size
mx_nm_len = len(max(dic,key=len))
mx_bk_len = max([len(max(books, key=len)) for books in dic.itervalues()])

# Store max name size + 1
mx = max([mx_nm_len, mx_bk_len]) + 1

# Store people
keys = dic.keys()

# Create generic format code to print neat list
fmat = ("%-"+str(mx)+"s")*len(keys)

# Print header line
print fmat % tuple(keys)

# similar to zip command but works for any number of lists
# Assumes all dic.values() are lists
# "zips" to longest list and uses None when any given list runs out of values
books = map(None, *dic.values())

# replaces None values in row outputs with empty strings and prints result using
# string format code (fmat)
for row in books:
    row = tuple([book if book!= None else "" for book in row])
    print fmat % row

Answer 3

重点是您没有以正确的方式定义数据。 Python定义第一个条目的方式与它的打印方式完全一致：单个字符串。如果您需要多个元素，则需要将元素定义为包含多个元素：

dic = {
  'Cohen'     : ['Calvino', 'Evertt', 'Borges'],
  'Larry'     : ['The Bible'], 
  'Volanski'  : ['Phone Book']
}

现在你可以这样做：

for key, value in dic.items():
    print "%s\t%s" % (key, "\t".join(value))

修改确定，没有看到您希望顶部的名称和标题向下。有点棘手，但这样做会：

import itertools
print "\t".join(dic.keys())
for books in itertools.izip_longest(*dic.values(), fillvalue=''):
    print "\t".join(books)

Answer 4

此解决方案可确保对输出进行排序，并确保项目在正确的列中显示。我使用expandtabs()设置标签长度，使其非常印刷。

import itertools

dic = {'Cohen':['Calvino', 'Evertt','Borges'],'Larry': ['The Bible'], 'Volanski'  :['Phone Book']}

sorted_keys = sorted(dic.keys())
for name in sorted_keys:
    print (name+'\t').expandtabs(15),
print
zippp = list(itertools.izip_longest(*[dic[i] for i in sorted_keys]))
for i in xrange(len(zippp[0])):
    for j in xrange(len(zippp)):
        if zippp[i][j]:
            print (zippp[i][j]+'\t').expandtabs(15),
    print

产地：

Cohen           Larry           Volanski       
Calvino         The Bible       Phone Book     
Evertt         
Borges

循环遍历字典并以特定格式打印

4 个答案: