Question

我已经复制粘贴了一个我正在尝试修改的函数。我想让它正确处理错误。现在，$smtpResponse不会返回任何值。当我在函数中回显值时，它们会显示，但$smtpResponse不会产生任何结果，也不会发送true或false值。

我也试过回复“失败”和“成功”，但他们没有表现出来。 $response没有显示，但“它有效！”确实。为什么函数不返回任何东西？

我正在尝试输出如下：

//Send e-mail  
$repsonse = authSendEmail($from, $namefrom, $sendto,"", $subject,$message);

//Report success/failure
echo $response;

The culprit: 

function authSendEmail($from, $namefrom, $to, $nameto, $subject, $message) {
    //Connect to the host on the specified port  
    $smtpConnect = fsockopen($smtpServer, $port, $errno, $errstr, 60);  
    $smtpResponse = fgets($smtpConnect, 515);  

    if(empty($smtpConnect)) {  
        $output = "Failed to connect: $smtpResponse";  
        echo $output;
        return "Fail";
         //return false; 
         //used to read 'return $output' 
    }  

    else {  
        $logArray['connection'] = "Connected: $smtpResponse";  
    }  

    //Request Auth Login  
    fputs($smtpConnect,"AUTH LOGIN" . $newLine);  
    $smtpResponse = fgets($smtpConnect, 515);  
    $logArray['authrequest'] = "$smtpResponse";  

    if(!$smtpResponse) {
        return "Fail";
    }

    //Send username  
    fputs($smtpConnect, base64_encode($username) . $newLine);  
    $smtpResponse = fgets($smtpConnect, 515);  
    $logArray['authusername'] = "$smtpResponse";  

    if(!$smtpResponse) {
        return "Fail";
    }

    //Send password  
    fputs($smtpConnect, base64_encode($password) . $newLine);  
    $smtpResponse = fgets($smtpConnect, 515);  
    $logArray['authpassword'] = "$smtpResponse";  

    if(!$smtpResponse) {
        return "Fail";
    }

    //Say Hello to SMTP  
    fputs($smtpConnect, "HELO $localhost" . $newLine);  
    $smtpResponse = fgets($smtpConnect, 515);  
    $logArray['heloresponse'] = "$smtpResponse";  

    if(!$smtpResponse) {
        return "Fail";
    }

    //Email From  
    fputs($smtpConnect, "MAIL FROM: $from" . $newLine);  
    $smtpResponse = fgets($smtpConnect, 515);  
    $logArray['mailfromresponse'] = "$smtpResponse";  

    if(!$smtpResponse) {
        return "Fail";
    }

    //Email To  
    fputs($smtpConnect, "RCPT TO: $to" . $newLine);  
    $smtpResponse = fgets($smtpConnect, 515);  
    $logArray['mailtoresponse'] = "$smtpResponse";  

    if(!$smtpResponse) {
        return "Fail";
    }

    //The Email  
    fputs($smtpConnect, "DATA" . $newLine);  
    $smtpResponse = fgets($smtpConnect, 515);  
    $logArray['data1response'] = "$smtpResponse";  

    if(!$smtpResponse) {
        return "Fail";
    }

    //Construct Headers  
    $headers = "MIME-Version: 1.0" . $newLine;  
    $headers .= "Content-type: text/html; charset=iso-8859-1" . $newLine;  
    $headers .= "To: ".$nameto." <".$to.">" . $newLine;  
    $headers .= "From: ".$namefrom." <".$from.">" . $newLine;  
    fputs($smtpConnect, "Subject: $subject\n$headers\n\n $message \n.\n");  
    $smtpResponse = fgets($smtpConnect, 515);  
    $logArray['data2response'] = "$smtpResponse";  

    if(!$smtpResponse) {
        return "Fail";
    }

    // Say Bye to SMTP  
    fputs($smtpConnect,"QUIT" . $newLine);   
    $smtpResponse = fgets($smtpConnect, 515);  
    $logArray['quitresponse'] = "$smtpResponse";   

    if(!$smtpResponse) {
        return "Fail";
    }

    echo "It worked!";
    return "Success"; 
    //insert var_dump here -- uncomment out the next line for debug info
    //var_dump($logArray);
}

Answer 1

:)你有一个错字

//Send e-mail  
$repsonse = authSendEmail($from, $namefrom, $sendto,"", $subject,$message);

//Report success/failure
echo $response;

您返回$ repsonse 并回显$ 回复

并记录在案。复制/粘贴别人的代码将不会带你到任何地方。如果你想学习自己编写程序代码，或者你真的需要复制/粘贴，试着去理解你复制/粘贴的内容。我不是故意只是给你一个忠告。祝你好运！

Answer 2

也许这太简单了，但你真的有这样一句话：

//Report success/failure echo $response;

回声只是评论的一部分，你需要把它放在一个新的界限上。

此外，您应该在退出函数之前关闭该套接字连接。

此外，成功时返回布尔值true，失败时返回false可能更好，恕我直言。

如何让此函数返回值？

2 个答案: