Question

我想在Post的添加形式中使用一个字段，在空格处展开它，并将每个单词保存为标记，HasAndBelongsToMany Post。因此，对于每个无法识别的标记，它将创建一个新标记，但如果标记已存在，则它将仅在posts_tags表中创建新的引用。我已经尝试过使用saveAll，saveAssociated和一些foreach hacks，我不确定它出错的地方，但我无法弄清楚如何保存关联数据。任何形式的如何从表单到数据库获取标签数据的概述将不胜感激。

//in model
public function parseTags($data) {
    $str = $data['Tag'][0]['title'];
    $tags = explode('',$str);
    for ($i=0; $i<count($tags); $i++) {
        $data['Tag'][$i]['title'] = $tags[$i];
    }
    return $data;
}

//in view
echo $this->Form->input('Tag.0.title',array('label'=>'Tags'));

//in controller
public function add() {
    if ($this->request->is('post')) {
        $this->Question->create();
        $this->request->data['Question']['user_id'] = $this->Auth->user('id');
        $this->request->data = $this->Question->parseTags($this->request->data);
        if ($this->Question->saveAll($this->request->data)) {
            $this->Session->setFlash(__('The question has been saved'), 'default', array('class' => 'success'));
            $this->redirect(array('action' => 'index'));
        } else {
            $this->Session->setFlash(__('The question could not be saved. Please, try again.'));
        }
    }
    $users = $this->Question->User->find('list');
    $this->set(compact('users'));
}

Answer 1

您必须首先检查标签是否已保存，如果未保存，您可以保存它。因此，在保存模型之前，之前会保存所有标记。

类似的东西：

/* $tag_list is exploded tags*/

        foreach ($tag_list as $tag) {
            $res = $this->Tag->find('first', array('conditions' => array('Tag.name' => $tag)));
            if ($res != array()) {
                $tag_info[] = $res['Tag']['id'];
            } else {
                $this->Tag->create();
                $this->Tag->save(array('Tag.name' => $tag));
                $tag_info[] = sprintf($this->Tag->getLastInsertID());
            }


        }
        $this->model->data['Tag']['Tag'] = $tag_info;

如何拆分HABTM标签？

1 个答案: