我对此声明有一些问题,
<?php
$cert_mess = $vehicle['make'];
if ($vehicle["make"] == "Honda" && $vehicle["Certified"] == "0") {
$cert_mess = "DFWCertAutos";
}
elseif ($vehicle["make"] == "Cadillac" && $vehicle["Certified"] == "0") {
$cert_mess = "DFWCertAutos";
}
elseif (!in_array($vehicle['make'], array('Cadillac','Honda') )) {
$cert_mess = "DFWCertAutos";
}
?>
<div style="font-size:10px; padding:10px; padding-top: 0px;">*This car is <?php
echo $cert_mess ?> certified.</div>
有什么建议吗?目前它只显示$cert_mess
为'make'并忽略if / else if语句。
答案 0 :(得分:1)
更简单的代码如下:
$cert_mess = $vehicle['make'];
if (($vehicle["make"] == "Honda" && $vehicle["Certified"] == "0")
|| ($vehicle["make"] == "Cadillac" && $vehicle["Certified"] == "0")
|| !in_array($vehicle['make'], array('Cadillac','Honda'))
) {
$cert_mess = "DFWCertAutos";
}
答案 1 :(得分:1)
更简单:
$cert_mess = $vehicle['make'];
if (!in_array($vehicle['make'], array('Cadillac', 'Honda')) || $vehicle['certified'] == '0')
{
$cert_mess = 'DFWCertAutos';
}