Question

使用PHP尝试解决此问题，但对其他解决方案（Python，Bash等）开放。

我有以下格式的csv数据：注意：商店名称ID（第1行和第6行）始终为10位数产品ID（col1，行2,3,4和7,8,9,10,11）始终为7位数。

Store name 0123456789,,,
0123456,product desc,1,1.00
1234567,product desc2,1,2.00
2345678,product desc3,1,3.00
Ship Total,6.00,,
Store name2 9876543210,,,
0123456,product desc,4,1.00
1234567,product desc2,2,2.00
2345678,product desc3,1,3.00
3456789,product desc4,3,4.00
45678901,product desc5,1,5.00
Ship Total,28.00,,

所需格式为：

0123456789,0123456,product desc,1,1.00
0123456789,1234567,product desc2,1,2.00
0123456789,2345678,product desc3,1,3.00
9876543210,0123456,product desc,4,1.00
9876543210,1234567,product desc2,2,2.00
9876543210,2345678,product desc3,1,3.00
9876543210,3456789,product desc4,3,4.00
9876543210,45678901,product desc5,1,5.00

我有一个以上述格式解析数据的程序。

我已经将商店放入一个数组，并将交易转换为另一个数组......只需将它们放在一起。

这是我到目前为止所得到的。



$csv = array();
$file = fopen($datafile, 'r');

while (($result = fgetcsv($file)) !== false)
{
    $csv[] = $result;
}

fclose($file);

foreach ($csv as $key => $value) { 
    if (preg_match('/\d{10}$/', $value[0],$store)) {
        $stores[$key] .= $store[0];
    }
}
print_r($stores);

foreach ($csv as $key => $value) {
    if (preg_match('/^\d{7}/', $value[0],$transaction)) {
        $transactions[$key] = array("Item"=>$value[0],"Desc"=>$value[1],"Qty"=>$value[2],"Price"=>$value[3]);
    }
}
print_r($transactions)

print_r结果：

$csv = array();
$file = fopen($datafile, 'r');

while (($result = fgetcsv($file)) !== false)
{
    $csv[] = $result;
}

fclose($file);

foreach ($csv as $key => $value) { 
    if (preg_match('/\d{10}$/', $value[0],$store)) {
        $stores[$key] .= $store[0];
    }
}
print_r($stores);

foreach ($csv as $key => $value) {
    if (preg_match('/^\d{7}/', $value[0],$transaction)) {
        $transactions[$key] = array("Item"=>$value[0],"Desc"=>$value[1],"Qty"=>$value[2],"Price"=>$value[3]);
    }
}
print_r($transactions)

回答后编辑。这是完美的。

[代码]



Array
(
    [0] => 0123456789
    [5] => 9876543210
)

Array
(
    [1] => Array
        (
            [Item] => 0123456
            [Desc] => product desc
            [Qty] => 1
            [Price] => 1.00
        )
...
... arrays 2,3,4,6,7,8,9....
...

    [10] => Array
        (
            [Item] => 45678901
            [Desc] => product desc5
            [Qty] => 1
            [Price] => 5.00
        )
)

[/代码]

Answer 1

$file = fopen($datafile, 'r'); 

$Out = '';
$LastStore = '';
while (($result = fgetcsv($file)) !== false) 
{ 
    if (preg_match('/\d{10}$/', $result[0],$store)) { 
        $LastStore = $store;
    } elseif (preg_match('/^\d{7}/', $result[0],$transaction)) { {
        $aT = array("Store"=>$LastStore, "Item"=>$transaction[0],"Desc"=>$transaction[1],"Qty"=>$transaction[2],"Price"=>$transaction[3])
        $Out .= implode(',', $aT) . "\n";

    }
} 
fclose($file); 

// Output as file (if this is as intended). Otherwise you have $Out to be the CSV string you need.    
file_put_contents($OutFileName, $Out);

或者，如果你想要一个大数组中的所有东西

$file = fopen($datafile, 'r'); 

$aT = array();
$LastStore = '';
while (($result = fgetcsv($file)) !== false) 
{ 
    if (preg_match('/\d{10}$/', $result[0],$store)) { 
        $LastStore = $store;
    } elseif (preg_match('/^\d{7}/', $result[0],$transaction)) { {
        $aT[] = array("Store"=>$LastStore, "Item"=>$transaction[0],"Desc"=>$transaction[1],"Qty"=>$transaction[2],"Price"=>$transaction[3])
    }
} 
fclose($file);

Answer 2

我会建议这样的事情

$handle = @fopen($datafile, "r");
if ($handle) {
    $Out = '';
    $Store = '';
    while (($buffer = fgets($handle)) !== false) {
        if (substr($buffer, 0, 5) == 'Store') {
            preg_match('/\d{10}/', $buffer, $storeId);
            $Store = $storeId[0] . ',';
        } else if (substr($buffer, 0, 4) == 'Ship') {
            // ignore
        } else {
            $Out .= $Store . $buffer . "\n";
        }
    }
}
fclose($handle);

file_put_contents('Results.txt', $Out);

将不规则的CSV数据提取到结构化数组中 - 尝试使用PHP

2 个答案: