Question

说我有一个字符串n = '22'而另一个数字a = 4，所以n是str而a是int。我想创建一组列表，如：

list1 = [22, 12, 2] #decreasing n by 10, the last item must be single digit, positive or 0
list2 = [22, 11, 0] #decreasing n by 11, last item must be single digit, positive or 0
list3 = [22, 21, 20] #decreasing n by 1, last item must have last digit 0
list4 = [22, 13] #decreasing n by 9, last item must be single digit. if last item is == a, remove from list
list5 = [22, 32] #increasing n by 10, last item must have first digit as a - 1
list6 = [22, 33] #increasing n by 11, last item must have first digit as a - 1
list7 = [22, 23] #increasing n by 1, last item must have last digit a - 1
list8 = [22, 31] #increasing n by 9, last item must have first digit a - 1

我正在努力解决这个问题。也许你可以告诉我如何解决这个问题？

顺便说一下，如果一个条件不能满足，那么只有n将在该列表上。比如n ='20'，a = 4：

list3 = [20]

这也适用于学校项目，列表中包含列表项的索引。我想不出更好的方法来解决这个问题。

Answer 1

这应该让你开始：

def lbuild( start, inc, test ):
    rslt = [start]
    while not test(start,inc):
        start += inc
        rslt.append( start )
    return rslt

n = '22'
a = 4

nval = int(n)
print lbuild( nval, -10, lambda(x,y): (x<10 and x>=0) )
print lbuild( nval, 1, lambda(x,y): x%10 == a-1 )

Python - 使用数字创建一组列表

1 个答案: