Question

我正在尝试将OpenLDAP和Active目录同步。为此，我使用了一个名为LSC-Project的程序，它被指定用于执行此类操作。

我已尽力配置程序但是我无法找到摆脱以下错误的方法：

javax.naming.NameNotFoundException: [LDAP: error code 32 - 0000208D: NameErr: DSID-
031001CD,
problem 2001 (NO_OBJECT), data 0, best match of:
'DC=domname,DC=com'
]; remaining name 
'uid=user1,ou=Users'

May 09 15:19:25 - ERROR - Error while synchronizing ID uid=user1,ou=Users:
java.lang.Exception:
Technical problem while applying modifications to directory
dn: uid=user1,ou=Users,dc=domname,dc=com
changetype: add
userPassword: 3+kU2th/WMo/v553A24a3SBw2kU=
objectClass: uid

这是程序运行的配置文件：

############################### 
Destination LDAP directory #
##############################

dst.java.naming.provider.url = ldap://192.168.1.3:389/dc=Windows,dc=com  
dst.java.naming.security.authentication = simple
dst.java.naming.security.principal = cn=Administrator,cn=Users,dc=Windows,dc=com
dst.java.naming.security.credentials = 11111
dst.java.naming.referral = ignore
dst.java.naming.ldap.derefAliases = never
dst.java.naming.factory.initial = com.sun.jndi.ldap.LdapCtxFactory
dst.java.naming.ldap.version = 3
dst.java.naming.ldap.pageSize = 1000

#########################
Source LDAP directory 
#########################

src.java.naming.provider.url = ldap://192.168.1.2:389/dc=Linux,dc=com
src.java.naming.security.authentication = simple
src.java.naming.security.principal = uid=root,ou=users,dc=Linux,dc=com
src.java.naming.security.credentials = 11111
src.java.naming.referral = ignore
src.java.naming.ldap.derefAliases = never
src.java.naming.factory.initial = com.sun.jndi.ldap.LdapCtxFactory
src.java.naming.ldap.version = 3

#######################
Tasks configuration 
#######################

lsc.tasks = Administrator
lsc.tasks.Administrator.srcService = org.lsc.jndi.SimpleJndiSrcService
lsc.tasks.Administrator.srcService.baseDn = ou=users
lsc.tasks.Administrator.srcService.filterAll = (&(objectClass=person))
lsc.tasks.Administrator.srcService.pivotAttrs = uid 
lsc.tasks.Administrator.srcService.filterId = (&(objectClass=person)(uid={uid}))
lsc.tasks.Administrator.srcService.attrs = description uid userPassword

lsc.tasks.Administrator.dstService = org.lsc.jndi.SimpleJndiDstService
lsc.tasks.Administrator.dstService.baseDn = cn=Users
lsc.tasks.Administrator.dstService.filterAll = (&(cn=*)(objectClass=organizationalPerson))
lsc.tasks.Administrator.dstService.pivotAttrs = cn, top, person, user, organizationalPerson
lsc.tasks.Administrator.dstService.filterId = (&(objectClass=user) (sAMAccountName={cn}))
lsc.tasks.Administrator.dstService.attrs = description cn userPassword objectClass

lsc.tasks.Administrator.bean = org.lsc.beans.SimpleBean
lsc.tasks.Administrator.dn = "uid=" + srcBean.getAttributeValueById("uid") + ",ou=Users"

dn.real_root = dc=Domname,dc=com

############################# 
Syncoptions configuration 
#############################

lsc.syncoptions.Administrator = org.lsc.beans.syncoptions.PropertiesBasedSyncOptions
lsc.syncoptions.Administrator.default.action = M
lsc.syncoptions.Administrator.objectClass.action = M
lsc.syncoptions.Administrator.objectClass.force_value = srcBean.getAttributeValueById("cn").toUpperCase()
lsc.syncoptions.Administrator.userPassword.default_value = SecurityUtils.hash(SecurityUtils.HASH_SHA1, "defaultPassword")
lsc.syncoptions.Administrator.default.delimiter=;
lsc.syncoptions.Administrator.objectClass.force_value = "top";"user";"person";"organizationalPerson"
lsc.syncoptions.Administrator.userPrincipalName.force_value = srcBean.getAttributeValueById("uid") + "@Domname.com"
lsc.syncoptions.Administrator.userAccountControl.create_value = AD.userAccountControlSet ( "0", [AD.UAC_SET_NORMAL_ACCOUNT])

我怀疑它与源配置部分中的任务配置的baseDn有关。

操作系统是ubuntu 10.04和Windows2K3

有人建议我在他们之间进行手动同步，但我没有找到任何指南。而且这个程序几乎是唯一能说这种工作没有成本的事情。

Answer 1

NameNotFoundException的主要原因是您搜索的对象不存在或您正在搜索的容器 不正确。

Answer 2

baseDn应该是搜索基础对象的可分辨名称，例如ou=users,dc=domname,dc=com。

另见

Answer 3

在Spring-ldap的情况下，当我们在上下文文件（LdapContextSource bean）中指定baseDn时，以及在createUser代码中构建userDn时，我们常常会遇到此错误。我们不需要在{{1}中再次指定dc }}

buildUserDn()

Answer 4

在Active Directory中：+----+----+------+ |key1|key2|result| +----+----+------+ | 2| 2| 2| | 2| 2| 2| | 1| 2| 1| | 1| 1| 3| | 1| 1| 3| | 1| 1| 3| | 1| 3| 1| | 2| 1| 1| +----+----+------+目录是Users类，而不是OrganizationalUnit，因此您应该使用：container

Ldap错误代码32

4 个答案:

另见