Question

我正在使用WOL PHP脚本，我希望找到一种方法来使用ajax刷新部分页面，或者我应该调用外部php脚本吗？

我的PHP脚本启动一台电脑，然后检查多次以查看它是否已启动并运行....但是，使用PHP时，用户显然必须等到它完成所有操作才会显示结果，我我希望有一种方法可以让我在运行的“while循环”运行并在页面的第一部分加载后更新？

本质上，checkstatus函数检查端口是否正在运行，然后显示输出..我希望加载主页面，然后使用ajax或其他php脚本更新portcheck的状态？不确定如何。

function CheckStatus($tries, $device, $deviceip, $deviceport, $devicemac1, $devicemac2, $maxtries, $broadcast, $udport, $timeout){
    while($tries <= $maxtries){
        echo "<br \>";
        echo "Try $tries of $maxtries";
        echo "<br \>";
        //echo portcheck($deviceip, $deviceport);
        if (portcheck($deviceip, $deviceport) != 0){
                echo "  ------>  Could NOT open connection to $device at $deviceip on port $deviceport";
                echo "<br \>";                
                //echo "<br /> TRIES: $tries";

            }else{
                echo "<br \>";
                echo "<br \>";
                echo "<br \>";
                echo "TESTED OKAY!  $device";
                return TRUE;
            }
            $tries=$tries + 1;
    }
    echo "<br />";
    echo "MAX TRIES REACHED... COULD NOT CONNECT!";
    return FALSE;
}

Answer 1

发布评论说“你不能在一个PHP的实例中做到这一点”我现在将继续并证明自己是错的。

可能使用某种server push设置执行此操作。请考虑以下代码：

<?php

  // Do all your preliminary stuff here

?>
<html>
  <head>
    <title>Server push demo</title>
    <script type="text/javascript">
      function updateTries(tries) {
        document.getElementById('num_tries').innerHTML = tries;
      }
      function pushEvent(str) {
        var event = document.createElement('div');
        event.innerHTML = str;
        document.getElementById('stream_container').appendChild(event);
      }
    </script>
  </head>
  <body>
    <div>
      Number of tries:
      <span id="num_tries"></span>
    </div>
    <div id="stream_container"></div>
<?php

  // Push all output so far to the client
  flush();

  // Start status check loop
  CheckStatus($tries, $device, $deviceip, $deviceport, $devicemac1, $devicemac2, $maxtries, $broadcast, $udport, $timeout);

  function CheckStatus($tries, $device, $deviceip, $deviceport, $devicemac1, $devicemac2, $maxtries, $broadcast, $udport, $timeout){

    while ($tries < $maxtries) {

        echo "<script type='text/javascript'>updateTries($tries);</script>";
        flush();

        if (portcheck($deviceip, $deviceport) != 0){

          echo "<script type='text/javascript'>pushEvent('Could NOT open connection to $device at $deviceip on port $deviceport');</script>";
          flush();

        } else {

          echo "<script type='text/javascript'>pushEvent('TESTED OKAY! $device');</script>";
          flush();
          return TRUE;

        }

        $tries++;

    }

    echo "<script type='text/javascript'>pushEvent('MAX TRIES REACHED... COULD NOT CONNECT!');</script>";
    flush();
    return FALSE;

  }

?>
</body></html>

但是，我仍然认为最好将循环抽象到客户端并使用AJAX轮询服务器，该服务器一次执行一次检查。

PHP while循环，使用ajax将信息更新到页面

1 个答案: