Question

我一直在互联网上搜索如何模拟蛋糕请求。我想要将数据函数存根，以使控制器中可用的$ this-＆gt; request-＆gt; data（'whatever'）。但我的测试用例出了点问题

$Jobs = $this->generate('Tasks' , array(
  'components' => array(        
    'RequestHandler' => array('isMobile','prefers','renderAs'))
));
// Mock CakeRequest
$request = $this->getMock('CakeRequest', array('_readInput'));      
$Jobs->RequestHandler->request = $request;

$Jobs->RequestHandler->request->expects($this->any())
  ->method('data')->with('anything')->will($this->returnValue('test'));

$result = $this->testAction('/tasks/test/',
            array('method' => 'get', 'return' => 'vars'));

每当我在控制器中调用$this->request->data('anything')时，它都会返回null！

请尽量帮助我

Answer 1

来自PhpUnit文档：

默认情况下，给定类的所有方法都替换为只返回NULL的测试double，除非使用will（$ this-＆gt; returnValue（））配置返回值。

当提供第二个（可选）参数时，只有名称在数组中的方法将替换为可配置的测试double。其他方法的行为不会改变。

所以你需要这样做：

$Jobs = $this->generate('Tasks' , array(
    'components' => array(        
    'RequestHandler' => array('isMobile','prefers','renderAs'))
));
// Mock CakeRequest
$request = $this->getMock('CakeRequest', array('_readInput'));      
$Jobs->RequestHandler->request = $request;

$Jobs->RequestHandler->request->expects($this->any())
    ->method('_readInput')->with('anything')->will($this->returnValue('test'));

$result = $this->testAction('/tasks/test/',
        array('method' => 'get', 'return' => 'vars'));

或者这个：

$Jobs = $this->generate('Tasks' , array(
    'components' => array(        
    'RequestHandler' => array('isMobile','prefers','renderAs'))
));
// Mock CakeRequest
$request = $this->getMock('CakeRequest', array('data'));      
$Jobs->RequestHandler->request = $request;

$Jobs->RequestHandler->request->expects($this->any())
    ->method('data')->with('anything')->will($this->returnValue('test'));

$result = $this->testAction('/tasks/test/',
        array('method' => 'get', 'return' => 'vars'));

因为我不知道cakePHP我不能告诉你哪个是正确的答案。但根据这个：http://api20.cakephp.org/view_source/controller-test-dispatcher （第232行），你应该尝试前一个。

mock cake请求存根数据功能

1 个答案: