一个简单的wsgi网站与python,但.css文件不加载。为什么?

时间:2012-05-15 17:03:30

标签: python css styles wsgi

当我在浏览器中转到localhost:8080时,为什么我的背景不是蓝色? 以下3个文件都位于同一目录中:

wsgiwebsite.py

#!/usr/bin/env python
from wsgiref.simple_server import make_server

cont = (open('wsgiwebsite_content.html').read())

def application(environ, start_response):
    start_response('200 OK', [('Content-Type', 'text/html')])
    return [cont]

server = make_server('0.0.0.0', 8080, application)
server.serve_forever()

wsgiwebsite_content.html

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html>
  <head>
    <link rel="stylesheet" type="text/css" href="wsgiwebsite_style.css">
  </head>

  <body>
    This is my first web page
  </body>
</html>

wsgiwebsite_style.css

body{background-color:blue;}

4 个答案:

答案 0 :(得分:1)

您尝试通过wsgi服务器加载css,但您的服务器始终只返回html文件。看看firebug / web inspector / ...来查看服务器对css文件的响应。

答案 1 :(得分:1)

WSGI只提供您的Python代码,甚至可能不知道该CSS文件的存在。

您可以将您的网络服务器配置为为您处理静态资产,或者使用static之类的内容来提供静态媒体。

答案 2 :(得分:1)

以下代码段仅供学习之用。我创建了一个静态目录并在那里保存了我的index.html和css文件,因此无法访问我自己的源代码文件。

from wsgiref.simple_server import make_server                                    
import os                                                                        


def content_type(path):                                                          
if path.endswith(".css"):                                                    
    return "text/css"                                                        
else:                                                                        
    return "text/html"                                                       


def app(environ, start_response):                                                
    path_info = environ["PATH_INFO"]                                             
    resource = path_info.split("/")[1]                                           

    headers = []                                                                 
    headers.append(("Content-Type", content_type(resource)))                     

    if not resource:                                                             
        resource = "index.html"                                                  

    resp_file = os.path.join("static", resource)                                 

    try:                                                                         
        with open(resp_file, "r") as f:                                          
            resp_file = f.read()                                                 
    except Exception:                                                            
        start_response("404 Not Found", headers)                                 
        return ["404 Not Found"]                                                 

    start_response("200 OK", headers)                                            
    return [resp_file]                                                           

s = make_server("0.0.0.0", 8080, app)                                            
s.serve_forever()                                              

答案 3 :(得分:0)

Denis代码几乎可以解决我的问题,但是我需要进行一些更改/修复,这就是我的工作方式:

from wsgiref.simple_server import make_server
from cgi import parse_qs, escape

import codecs                                                                       
                                                                             
                                                                             
def tipoDeConteudo(path):
    if path.endswith(".css"):
        return "text/css"
    else:
        return "text/html"                                                       
                                                                             
                                                                             
def web_app(environment, response):                                                
    caminho = environment["PATH_INFO"]
    resource = caminho.split("/")[1]

    headers = []
    headers.append(("Content-Type", tipoDeConteudo(resource)))                   
                                                                             
    try:
        resp_file = codecs.open("indexResposta.html", 'r').read()
    except Exception:
        response("404 Not Found", headers)
        return ["404 Not Found"]                                                 
                                                                             
    response('200 OK', headers)
    return [resp_file.encode()]                                                        
                                                                             
s = make_server("0.0.0.0", 8080, app)                                            
s.serve_forever()