我有不同的选择如何将我的GUID存储为字符串行。
1. Accessibility|5102d73a-1b0b-4461-93cd-0c024738c19e
2. 5102d73a-1b0b-4461-93cd-0c024738c19e;#5102d73a-1b0b-4461-93cd-0c024733d52d
3. |;#5102d73a-1b0b-4461-93cd-0c024738c19e;#SharePointTag|5102d73a-1b0b-4461-93cd-0c024733d52d
3. Business pages|;#5102d73a-1b0b-4461-93cd-0c024738cz13;#SharePointTag|5102d73a-1b0b-4461-93cd-0c024733d52d
你能帮助我解决这个问题吗?我怎么能解析这个标签并最终得到Guids类型?也许正则表达可以帮助这种情况?
答案 0 :(得分:5)
看起来您正在玩托管元数据,期限商店ID和字词集ID:)
只需使用常规正则表达式(下面的“p”变量):
string c1 = "Accessibility|5102d73a-1b0b-4461-93cd-0c024738c19e";
string c2 = "5102d73a-1b0b-4461-93cd-0c024738c19e;#5102d73a-1b0b-4461-93cd-0c024733d52d";
string c3 = "|;#5102d73a-1b0b-4461-93cd-0c024738c19e;#SharePointTag|5102d73a-1b0b-4461-93cd-0c024733d52d";
string c4 = "Business pages|;#5102d73a-1b0b-4461-93cd-0c024738cz13;#SharePointTag|5102d73a-1b0b-4461-93cd-0c024733d52d";
string p = @"([a-zA-Z0-9]{8}[-][a-zA-Z0-9]{4}[-][a-zA-Z0-9]{4}[-][a-zA-Z0-9]{4}[-][a-zA-Z0-9]{12})";
MatchCollection mc;
Console.WriteLine("#1");
mc = Regex.Matches(c1, p);
foreach (var id in mc)
Console.WriteLine(id);
Console.WriteLine("#2");
mc = Regex.Matches(c2, p);
foreach (var id in mc)
Console.WriteLine(id);
Console.WriteLine("#3");
mc = Regex.Matches(c3, p);
foreach (var id in mc)
Console.WriteLine(id);
Console.WriteLine("#4");
mc = Regex.Matches(c4, p);
foreach (var id in mc)
Console.WriteLine(id);
输出:
#1
5102d73a-1b0b-4461-93cd-0c024738c19e
#2
5102d73a-1b0b-4461-93cd-0c024738c19e
5102d73a-1b0b-4461-93cd-0c024733d52d
#3
5102d73a-1b0b-4461-93cd-0c024738c19e
5102d73a-1b0b-4461-93cd-0c024733d52d
#4
5102d73a-1b0b-4461-93cd-0c024738cz13
5102d73a-1b0b-4461-93cd-0c024733d52d
Press any key to continue...
答案 1 :(得分:4)
var possibleGuids = myString.Split("|;#".ToCharArray(),
StringSplitOptions.RemoveEmptyEntries);
Guid g;
foreach(var poss in possibleGuids)
{
if(Guid.TryParse(poss, out g))
{
// g contains a guid!
}
}
答案 2 :(得分:2)
string sContent = "your data"; // any of your four forms of input
string sPattern = @"([a-z0-9]*[-]){4}[a-z0-9]*";
MatchCollection mc = Regex.Matches(sContent, sPattern );
foreach (var sGUID in mc)
{
// Do whatever with sGUID
}
答案 3 :(得分:1)
您可以拆分字符串,例如
"fist|second".Split('|')
您获得GUID字符串后,使用
将其转换为GUID Guid = new Guid(myString);
第一行
var guid = new Guid("Accessibility|5102d73a-1b0b-4461-93cd-0c024738c19e".Split("|")[1]);
第二行
var myArray = "5102d73a-1b0b-4461-93cd-0c024738c19e;#5102d73a-1b0b-4461-93cd-0c024733d52d".Split(';');
var guid1 = new Guid(myArray[0]);
var guid2 = new Guid(myArray[1].Replace('#',''));
所以你可以这样继续......