Question

我正在使用OpenPop.net尝试解析来自给定收件箱中所有电子邮件的链接。我找到了这个方法来获取所有信息：

    public static List<OpenPop.Mime.Message> FetchAllMessages(string hostname, int port, bool useSsl, string username, string password)
    {
        // The client disconnects from the server when being disposed
        using (Pop3Client client = new Pop3Client())
        {
            // Connect to the server
            client.Connect(hostname, port, useSsl);

            // Authenticate ourselves towards the server
            client.Authenticate(username, password);

            // Get the number of messages in the inbox
            int messageCount = client.GetMessageCount();

            // We want to download all messages
            List<OpenPop.Mime.Message> allMessages = new List<OpenPop.Mime.Message>(messageCount);

            // Messages are numbered in the interval: [1, messageCount]
            // Ergo: message numbers are 1-based.
            // Most servers give the latest message the highest number
            for (int i = messageCount; i > 0; i--)
            {
                allMessages.Add(client.GetMessage(i));                    
            }

            client.Disconnect();

            // Now return the fetched messages
            return allMessages;
        }
    }

现在我正在尝试遍历每条消息，但我似乎无法弄清楚如何做到这一点，到目前为止我的按钮已经有了这个：

    private void button7_Click(object sender, EventArgs e)
    {

        List<OpenPop.Mime.Message> allaEmail = FetchAllMessages("pop3.live.com", 995, true, "xxxxx@hotmail.com", "xxxxx");

        var message = string.Join(",", allaEmail);
        MessageBox.Show(message);
    }

我如何遍历allaEmail中的每个条目，以便我可以在MessageBox中显示它？

Answer 1

我可以看到您使用OpenPop主页中的fetchAllEmail example。类似的示例showing how to get body text也在主页上。

您可能还想了解电子邮件的实际结构。为此目的存在email introduction。

说完了，我会做类似下面代码的事情。

private void button7_Click(object sender, EventArgs e)
{
    List<OpenPop.Mime.Message> allaEmail = FetchAllMessages(...);

    StringBuilder builder = new StringBuilder();
    foreach(OpenPop.Mime.Message message in allaEmail)
    {
         OpenPop.Mime.MessagePart plainText = message.FindFirstPlainTextVersion();
         if(plainText != null)
         {
             // We found some plaintext!
             builder.Append(plainText.GetBodyAsText());
         } else
         {
             // Might include a part holding html instead
             OpenPop.Mime.MessagePart html = message.FindFirstHtmlVersion();
             if(html != null)
             {
                 // We found some html!
                 builder.Append(html.GetBodyAsText());
             }
         }
    }
    MessageBox.Show(builder.ToString());
}

我希望这可以帮助你。请注意，OpenPop还有online documentation。

Answer 2

我就这样做了：

string Body = msgList[0].MessagePart.MessageParts[0].GetBodyAsText();
            foreach( string d in Body.Split('\n')){
                Console.WriteLine(d);                    
            }

希望它有所帮助。

Answer 3

此问题中的其他答案不完整且不正确，主要是因为它们从未使用过至关重要的FindAllTextVersions方法。

这是获取实际正文内容的完整方法：

private static string GetMessageBodyAsText(Message message)
{
    try
    {
        List<MessagePart> list = message.FindAllTextVersions();

        // First let's try getting the plain text part:
        foreach (MessagePart part in list)
        {
            if (part != null)
            {
                return part.GetBodyAsText();
            }
        }

        // Now let's try getting the HTML part
        MessagePart html = message.FindFirstHtmlVersion();
        if (html != null)
        {
            return html.GetBodyAsText();
        }
        return null;
    }
    catch (Exception exc)
    {
        // Handle your exception here
        return null;
    }
}

OpenPop.net获取实际的消息文本

3 个答案: