Question

我的问题非常简单。我从sql select中得到一个如下所示的值：

ARAMAUBEBABRBGCNDKDEEEFOFIFRGEGRIEISITJPYUCAKZKG

我需要这样：

AR,AM,AU,BE,BA,BR,BG,CN,DK,DE,EE,FO,FI,FR,GE,GR,IE,IS,IT,JP,YU,CA,KZ,KG

每个数据集的长度不同。我尝试使用format（），stuff（）等等，但没有给我带来我需要的结果。

提前致谢

Answer 1

更新简历的时间。

create function DontDoThis (
    @string varchar(max),
    @count int
)
returns varchar(max)
as
begin
    declare @result varchar(max) = ''
    declare @token varchar(max) = ''

    while DATALENGTH(@string) > 0
    begin
        select @token = left(@string, @count) 
        select @string = REPLACE(@string, @token, '')
        select @result += @token + case when DATALENGTH(@string) = 0 then '' else ',' end
    end

    return @result
end

呼叫：

declare @test varchar(max) = 'ARAMAUBEBABRBGCNDKDEEEFOFIFRGEGRIEISITJPYUCAKZKG'
select dbo.DontDoThis(@test, 2)

Answer 2

在numbers table和for xml path的帮助下。

-- Sample table 
declare @T table
(
  Value nvarchar(100)
)

-- Sample data
insert into @T values
('ARAMAU'),
('ARAMAUBEBABRBGCNDKDEEEFOFIFRGEGRIEISITJPYUCAKZKG')


declare @Len int
set @Len = 2;

select stuff(T2.X.value('.', 'nvarchar(max)'), 1, 1, '')
from @T as T1
  cross apply (select ','+substring(T1.Value, 1+Number*@Len, @Len)
               from Numbers
               where Number >= 0 and 
                     Number < len(T1.Value) / @Len
               order by Number
               for xml path(''), type) as T2(X)

试试SE-Data

Answer 3

gbn的评论是完全正确的，如果不是非常外交的话:) TSQL是一种糟糕的字符串操作语言，但如果你编写一个CLR函数来做到这一点，那么你将拥有两全其美：.NET字符串函数调用纯TSQL。

Answer 4

我相信这就是QQping正在寻找的。

-- select .dbo.DelineateEachNth('ARAMAUBEBABRBGCNDKDEEEFOFIFRGEGRIEISITJPYUCAKZKG',2,',')

create function DelineateEachNth
(   
    @str varchar(max), -- Incoming String to parse
    @length int, -- Length of desired segment
    @delimiter varchar(100) -- Segment delimiter (comma, tab, line-feed, etc)
)
returns varchar(max)
AS
begin

    declare @resultString varchar(max) = ''
    -- only set delimiter(s) when lenght of string is longer than desired segment
    if LEN(@str) > @length
    begin
        -- continue as long as there is a remaining string to parse
        while len(@str) > 0
        begin
            -- as long as know we still need to create a segment...
            if LEN(@str) > @length
            begin
                -- build result string from leftmost segment length
                set @resultString = @resultString + left(@str, @length) + @delimiter
                -- continually shorten result string by current segment
                set @str = right(@str, len(@str) - @length)
            end
            -- as soon as the remaining string is segment length or less,
            --  just use the remainder and empty the string to close the loop
            else            
            begin
                set @resultString = @resultString + @str
                set @str = ''
            end
        end
    end
    -- if string is less than segment length, just pass it through
    else
    begin  
        set @resultString = @str
    end
    return @resultString 
end

Answer 5

在Regex

的帮助下

select Wow= 
(select case when MatchIndex %2 = 0 and MatchIndex!=0 then ',' + match else match end
  from dbo.RegExMatches('[^\n]','ARAMAUBEBABRBGCNDKDEEEFOFIFRGEGRIEISITJPYUCAKZKG',1)
  for xml path(''))

在值中每隔第n个字符添加逗号

5 个答案: