Question

我有一个包含动物图像的数组，另一个数组包含相应的动物声音，最后一个包含动物的名字。例如：

imagesArray：

0：[UIImage imageNamed:@"Elephant.png"]
1：[UIImage imageNamed:@"Dog.png"]
2：[UIImage imageNamed:@"Cat.png"]

soundsArray：

0：Elephant.mp3
1：Dog.mp3
2：Cat.mp3

wordsArray：

0：大象
1：狗
2：猫

它们是同步的并且与同一个计数器一起工作。我想在开始时将它们随机排列在新的3个数组中，但我希望所有3个数组中相同的动物细节（图像或声音或单词）相同。例如，新数组应如下所示：

imagesArray：

0：[UIImage imageNamed:@"Cat.png"]
1：[UIImage imageNamed:@"Dog.png"]
2：[UIImage imageNamed:@"Elephant.png"]

soundsArray：

0：Cat.mp3
1：Dog.mp3
2：Elephant.mp3

wordsArray：

0：猫
1：狗
2：大象

我把这段代码编写到视图中加载了：

theNewAnimalsPicture = [NSArray arrayWithObjects:[UIImage imageNamed:@"Square_Bee.png"],[UIImage imageNamed:@"Square_Bird.png"],[UIImage imageNamed:@"Square_Cat.png"],[UIImage imageNamed:@"Square_Chicken.png"],[UIImage imageNamed:@"Square_Cow.png"],[UIImage imageNamed:@"Square_Dog.png"],[UIImage imageNamed:@"Square_Elephant.png"],[UIImage imageNamed:@"Square_Frog.png"],[UIImage imageNamed:@"Square_Horse.png"],[UIImage imageNamed:@"Square_Lion.png"],[UIImage imageNamed:@"Square_Monkey.png"],[UIImage imageNamed:@"Square_Sheep.png"], nil];
theNewAnimalsSound = [NSArray arrayWithObjects:@"Bee.mp3",@"Bird.mp3",@"Miao.mp3",@"Chicken.mp3",@"Cow.mp3",@"Waff.mp3",@"Elephant2.mp3",@"Frog.mp3",@"Horse.mp3",@"LionSound.mp3",@"Monkey_Sound.mp3",@"Sheep.mp3", nil];
theNewAnimalsWord = [NSArray arrayWithObjects:@"Bee",@"Bird",@"Cat",@"Chicken",@"Cow",@"Dog",@"Elephant",@"Frog",@"Horse",@"Lion",@"Monkey",@"Sheep", nil];

for (int i =0;i<[theNewAnimalsPicture count];i++)
{
    int number = arc4random() % [theNewAnimalsPicture count];
    [PicturesAnimalArray addObject:[theNewAnimalsPicture objectAtIndex:number]];
    [SoundsAnimalArray addObject:[theNewAnimalsSound objectAtIndex:number]];
    [wordAnimalArray addObject:[theNewAnimalsWord objectAtIndex:number]];
    [theNewAnimalsPicture removeObjectAtIndex:number];
    [theNewAnimalsSound removeObjectAtIndex:number];
    [theNewAnimalsWord removeObjectAtIndex:number];
}

它不起作用。为什么会这样，我怎么能比我在这里做的更有效呢？

Answer 1

这里最好的办法是创建一个封装一个单词，声音和图片的类。

Animal.h

@interface Animal : NSObject
{
}

@property (nonatomic, retain) UIImage *picture;
@property (nonatomic, copy) NSString *word;
@property (nonatomic, copy) NSString *soundFile;

+ animalWithPicture:(UIImage *) aPicture word:(NSString *) aWord soundFile:(NSString *) aSoundFile;
- initWithPicture:(UIImage *) aPicture word:(NSString *) aWord soundFile:(NSString *) aSoundFile;

@end

Animal.m

#import "Animal.h"

@implementation Animal
@synthesize picture = _picture;
@synthesize word = _word;
@synthesize soundFile = _soundFile;

+ animalWithPicture:(UIImage *) aPicture word:(NSString *) aWord soundFile:(NSString *) aSoundFile
{
    return [[[self alloc] initWithPicture:aPicture word:aWord soundFile:aSoundFile] autorelease];
}

- initWithPicture:(UIImage *) aPicture word:(NSString *) aWord soundFile:(NSString *) aSoundFile
{
    self = [super init];
    if (!self) return nil;

    // WARNING, make sure you understand the side effects of using
    // the property accessor methods during "init" and "dealloc".
    // In this case, there should be no issue.

    self.picture = aPicture;
    self.word = aWord;
    self.soundFile = aSoundFile;

    return self;
}

- (void) dealloc
{
    self.picture = nil;
    self.word = nil;
    self.soundFile = nil;
    [super dealloc];
}

@end

然后，您可以只使用一个数组来包含每个动物对象。考虑将动物信息存储在plist文件中，而不是硬编码像我在这里所做的那样：

NSMutableArray *animals = [NSMutableArray array];

[animals addObject:[Animal animalWithPicture:[UIImage imageNamed:@"Square_Bee.png"] word:@"Bee" soundFile:@"Bee.mp3"]];
// ... etc ...
[animals addObject:[Animal animalWithPicture:[UIImage imageNamed:@"Square_Sheep.png"] word:@"Sheep" soundFile:@"Sheep.mp3"]];

有关在init和dealloc中使用访问者方法的原因的信息，请参阅this answer。

Answer 2

你可以做的另一种方法是创建一个新对象，比如'Animal'。具有三个属性的Animal对象：图片，声音，名称。

然后，您可以使用单个数组并将动物对象添加到数组中。然后迭代数组。

Answer 3

我不会直接将图像数据存储在数组中。相反，您可以存储图像文件名。
从数组中删除对象时，会重新编制索引。

您可以使用NSDictionary存储图像文件名，声音文件名和单词组合集。

示例代码：

#define kImageFileName   @"ImageFileName"
#define kSoundFileName     @"SoundFileName"
#define kWord           @"Word" 


NSDictionary *animalRecord = [[NSDictionary alloc]initWithObjectsAndKeys:
                              @"Square_Bee.png", kImageFileName,
                              @"bee.mp3", kSoundFileName,
                              @"Bee", kWord,                              
                              nil];

NSMutableArray *myArray = [[NSMutableArray alloc]init];
[myArray addObject:animalRecord];
// you would need to create some kind of loop and create animalRecord and add it to your myArray for all your picture/sound/word comnination sets.


//To retreive each record
int i = 0; // for example
NSString *imageFileName = [[myArray objectAtIndex:i] objectForKey:kImageFileName];  //with the filename, you can can the image whenever you need
NSString *soundFileName = [[myArray objectAtIndex:i] objectForKey:kSoundFileName];
NSString *word  = [[myArray objectAtIndex:i] objectForKey:kWord];

//to rearrange myArray's objects in random order, try this


 // This piece of code is from this [SO][1]
NSUInteger count = myArray.count;
for (NSUInteger i = 0; i < count; ++i) 
{
    // Select a random element between i and end of array to swap with.
    int nElements = count - i;
    int n = (arc4random() % nElements) + i;
    [myArray exchangeObjectAtIndex:i withObjectAtIndex:n];
}

链接到数组重新排列SO

如何在多个相应的NSMutableArrays中随机重新排列数据？

3 个答案:

Animal.h

Animal.m