我正在查看具有大量条目的访问日志,例如:
localhost_access_log.2012-05-07.txt:129.223.57.10 - - [07/May/2012:00:02:11 +0000] 2434 "POST /maker/www/jsp/opp/OpportunityForm.do HTTP/1.1" 302 - "https://dm2.myjones.com/maker/www/jsp/opp/Opportunity.jsp?screenDisplay={0}&forecastIcon={1}" "Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; .NET4.0C; .NET4.0E; InfoPath.2; MS-RTC LM 8)"
日期时间戳之后的数字是执行时间,引号中的字符串是URL。
我希望sed,URL和响应时间,并以格式
URL, response time
e.g。
POST /maker/www/jsp/opp/OpportunityForm.do HTTP/1.1, 2434
答案 0 :(得分:2)
sed
:
sed 's/^[^]]\+\] \([[:digit:]]\+\) \("[^"]\+"\).*/\2,\1/' inputfile
的Perl:
perl -lne 'print "$2,$1" if /.*? (\d+) (".*?")/'
答案 1 :(得分:1)
您可以使用awk
打印第6,第7,第8和第9个条目,如下所示:
awk '{print $7, $8, $9, ", " $6}' <access_log>
输出:"POST /maker/www/jsp/opp/OpportunityForm.do HTTP/1.1" , 2434
awk
按空格分隔字段。 nth
存储在$n
中。所以在你的输入行:
$7: "POST
$8: /maker/www/jsp/opp/OpportunityForm.do
$9: HTTP/1.1"
$6: 2434