Question

我使用以下代码迭代plist来查找字符串然后我想使用键的值 - 分数和数字不幸的是有些东西不起作用，我无法弄清楚

任何帮助将不胜感激

    NSString *theNumber = @"0.0075";

    BOOL found = NO;
    NSUInteger f;
    for (f = 0; f < [selectorKeysFractions count]; f++) {
        NSString * stringFromArray = [selectorKeysFractions objectAtIndex:f];
        if ([theNumber isEqualToString:stringFromArray]) {
            found = YES;
            break;
        }
    }
    if ( found ) {

        // do found
        //this line fails with unrecognised selector message          
        NSLog(@"%@",[[selectorKeysFractions objectAtIndex:f]objectForKey:@"fraction"]);

    } else {
        // do not found

    }

我的plist数据看起来像这样

<plist version="1.0">
<dict>
<key>fraction</key>
<string>1/128</string>
<key>number</key>
<string>23.78</string>
</dict>
<dict>
<key>fraction</key>
<string>1/234</string>
<key>number</key>
<string>25</string>
</dict>
</plist>

我正在设置像这样的数组

 NSString *path2 = [[NSBundle mainBundle] pathForResource:@"Fractions" ofType:@"plist"];
 pickerData2 =[[NSDictionary alloc]initWithContentsOfFile:path2];
 selectorKeysFractions = [[NSArray alloc] initWithArray:[pickerData2 allKeys]];

我做错了什么但是弄不清楚请帮忙

感谢

Answer 1

将消息“objectForKey”发送到NSString的对象。您必须要求您的NSDictionary才能获得正确的条目。

检查一下：

NSLog(@"%@",[pickerData2 objectForKey:[selectorKeysFractions objectAtIndex:f]]);

这应该返回你的字符串。

plist中的nsarray无法返回键值

1 个答案: