Question

我在Regex很糟糕，非常感谢这个问题的任何帮助，我认为对于任何熟悉的人来说都是新手。

我从REST调用中得到这样的响应

    {"responseData":{"translatedText":"Ciao mondo"},"responseDetails":"","responseStatus":200,"matches":[{"id":"424913311","segment":"Hello World","translation":"Ciao mondo","quality":"74","reference":"","usage-count":50,"subject":"All","created-by":"","last-updated-by":null,"create-date":"2011-12-29 19:14:22","last-update-date":"2011-12-29 19:14:22","match":1},{"id":"0","segment":"Hello World","translation":"Ciao a tutti","quality":"70","reference":"Machine Translation provided by Google, Microsoft, Worldlingo or the MyMemory customized engine.","usage-count":1,"subject":"All","created-by":"MT!","last-updated-by":null,"create-date":"2012-05-14","last-update-date":"2012-05-14","match":0.85}]}

我所需要的就是那些引文之间的'Ciao mondo'。我希望使用Java的Split功能，我可以做到这一点，但不幸的是它不允许两个单独的分隔符，因为我可以在翻译之前指定文本。

为了简化，我坚持的是正则表达式，以收集在translateText“：”和下一个“

之间的任何内容

我非常感谢任何帮助

Answer 1

您可以使用\"translatedText\":\"([^\"]*)\"表达式来捕获匹配项。

表达式含义如下：找到引用translatedText后跟冒号和开头引号。然后匹配以下引号之前的每个字符，并将结果捕获到捕获组。

String s = " {\"responseData\":{\"translatedText\":\"Ciao mondo\"},\"responseDetails\":\"\",\"responseStatus\":200,\"matches\":[{\"id\":\"424913311\",\"segment\":\"Hello World\",\"translation\":\"Ciao mondo\",\"quality\":\"74\",\"reference\":\"\",\"usage-count\":50,\"subject\":\"All\",\"created-by\":\"\",\"last-updated-by\":null,\"create-date\":\"2011-12-29 19:14:22\",\"last-update-date\":\"2011-12-29 19:14:22\",\"match\":1},{\"id\":\"0\",\"segment\":\"Hello World\",\"translation\":\"Ciao a tutti\",\"quality\":\"70\",\"reference\":\"Machine Translation provided by Google, Microsoft, Worldlingo or the MyMemory customized engine.\",\"usage-count\":1,\"subject\":\"All\",\"created-by\":\"MT!\",\"last-updated-by\":null,\"create-date\":\"2012-05-14\",\"last-update-date\":\"2012-05-14\",\"match\":0.85}]}";
System.out.println(s);
Pattern p = Pattern.compile("\"translatedText\":\"([^\"]*)\"");
Matcher m = p.matcher(s);
if (!m.find()) return;
System.out.println(m.group(1));

此片段prints Ciao mondo。

Answer 2

使用预测和后视来收集引号内的字符串：（？＆LT = [{}：] \ “）。？*（？= \”）

class Test
{
    public static void main(String[] args)
    {
        Scanner scanner = new Scanner(System.in);
        String in = scanner.nextLine();

        Matcher matcher = Pattern.compile("(?<=[,.{}:]\\\").*?(?=\\\")").matcher(in);

        while(matcher.find())
            System.out.println(matcher.group());
    }
}

Answer 3

试试这个正则表达式 -

^.*translatedText":"([^"]*)"},"responseDetails".*$

匹配组将包含Ciao mondo文本。

这假设translatedText和responseDetails将始终出现在样本中指定的位置。

正则表达式 - 文字字符串和引号之间的匹配

3 个答案: