Question

我想回到上一个视图控制器，当我点击我的搜索显示控制器的取消按钮时，我使用了代码：

[self.navigationController popToViewController: [self.navigationController.viewControllers objectAtIndex:0] animated:YES];

但是它给了我以下错误：

* 由于未捕获的异常'NSInternalInconsistencyException'而终止应用，原因：'搜索内容导航控制器不能在-setActive：YES和之间切换 -SETACTIVE：否'

Answer 1

[self.navigationController popViewControllerAnimated：YES];

将返回到此导航控制器中堆叠的上一个视图控制器。应该这样做..

Answer 2

我的问题是搜索显示控制器无法通过uinavigator setActive所以我通过添加以下代码来解决我的问题：

[self.searchDisplayController setActive：NO];

[self.navigationController popViewControllerAnimated：YES];

错误是：

*断言失败 - [UISearchDisplayController setActive：animated：]，/ SourceCache / UIKit_Sim / UIKit-1914.84 / UISearchDisplayController.m：617 2012-05-13 19：07：44.696 MyApp [3648：11903] * 由于未捕获的异常'NSInternalInconsistencyException'终止应用程序，原因：'搜索内容导航控制器不能在-setActive：YES和-setActive之间切换： NO'

Answer 3

我遇到了同样的问题并找到了解决方案。

诀窍不是让searchDisplayController在-setActive:animated:的任何地方拨打-viewWillDisappear。所以你应该让你的视图控制器成为searchBar的代表（以点击“取消”按钮）并在searchDisplayController变为活动状态时在背景上放置一个隐藏按钮（以捕捉空屏幕空间上的点击））。

在视图控制器中实现以下方法：

- (void)viewWillDisappear:(BOOL)animated
{
    [super viewWillDisappear:animated];
    [self.searchDisplayController setActive:NO animated:animated];
}

- (void)searchBarCancelButtonClicked:(UISearchBar *)searchBar
{
    [self.navigationController popViewControllerAnimated:YES];
}

- (void)backgroundClicked:(id)sender
{
    [self.navigationController popViewControllerAnimated:YES];  
}


- (void)searchDisplayControllerDidBeginSearch:(UISearchDisplayController *)controller
{
    UIButton *button = [UIButton buttonWithType:UIButtonTypeCustom];
    [button addTarget:self action:@selector(backgroundClicked:) forControlEvents:UIControlEventTouchUpInside];

    CGFloat searchBarHeight = controller.searchBar.frame.size.height;
    button.frame = CGRectOffset(self.view.bounds, 0.f, searchBarHeight) ;
    [self.view addSubview:button];
}

Answer 4

如果您只需要返回上一个视图，只需在navigationcontroller上添加一个后退按钮，您就可以单击它返回： -

你不需要popToViewController

UIBarButtonItem *backButton = [[UIBarButtonItem alloc] initWithTitle:@"Back"
      style:UIBarButtonItemStylePlain target:nil action:nil];
self.navigationItem.backBarButtonItem = backButton;
[backButton release];

或者如果你真的想要弹出视图，请使用： -

UINavigationController *navController = self.navigationController;      

    [UIView beginAnimations:nil context:NULL]; 
[UIView setAnimationDuration: 0.7];
    [UIView setAnimationTransition:<#UIViewAnimationTransitionCurlDown#> forView:navController.view cache:NO];

    [navController popViewControllerAnimated:NO];

    [UIView commitAnimations];

Answer 5

索引0处的对象是根视图控制器。所以它是堆栈中的第一个对象。但你只能弹出最后一个对象。而不是使用

[self.navigationController popToViewController: [self.navigationController.viewControllers objectAtIndex:0] animated:YES];

使用

[self.navigationController popToViewController: [self.navigationController.viewControllers lastObject] animated:YES];

或

[self.navigationController popToViewControllerAnimated:YES];

如何实现正确的uinavigationbar后退按钮功能

5 个答案: