这个请求有什么问题?

时间:2012-05-12 12:19:33

标签: java javascript jquery ajax jersey

我正在尝试对球衣测试方法发布请求。但我总是得到一个错误,不知道,有什么不对。我正在使用Tomcat。

Java代码:

@Path("/users")
public class UsersResource {
@GET
@Produces(MediaType.TEXT_PLAIN)
public String sayHello() {
    return "Hello Jersey Today";
}

@POST
@Consumes(MediaType.APPLICATION_JSON)
@Produces(MediaType.APPLICATION_JSON)
public String createUser(User us)
{
    //System.out.println("userdata " + us);
    User user = new User("testUserName", "testPassword");
    return user.toJson();
}
}

用户类:

import com.google.gson.Gson;
import com.google.gson.GsonBuilder;

public class User 
{
private String username;
private String password;

public User()
{
    super();
}

public User(String name, String pass)
{
    super();
    this.username = name;
    this.password = pass;
}

public User(String username)
{
    this.username = username;
}

public String getUsername() {
    return username;
}

public void setUsername(String username) {
    this.username = username;
}

public String getPassword() {
    return password;
}

public void setPassword(String password) {
    this.password = password;
}

public String toJson()
{
    Gson gson = new GsonBuilder().setPrettyPrinting().create();
    String json = gson.toJson(this);
    return json;
}
}

和js代码:

$(function () {

main = {

    // Start updates
    start: function(){

        var user = {username: "test", password: "pass"};
        var encoded = $.toJSON( user );

        ajaxPost.ajaxRequest("TodoListing/rest/users", user,
                            function(data)
                            {
                                alert("success with data " + data);
                            }, 

                            function(jqXHR, textStatus, errorThrown) {
                            alert("error " + textStatus + "/" + errorThrown);
                            });

    }
},

// Ajax request.
ajaxPost = {
    ajaxRequest: function(service, data, successSelector, errorSelector) {
        $.ajax({
            type: 'POST',
            url: ajaxPost.serverURL + service,
            data: data,
            contentType: "application/json",
            dataType: "application/json",
            success: successSelector,
            error: errorSelector
        });
    },
    serverURL: 'http://localhost/',
};

});

JS总是在没有描述的情况下返回错误(空的errorThrown),并且jersey在请求时记录错误:

PM com.sun.jersey.server.wadl.generators.WadlGeneratorJAXBGrammarGenerator attachTypes
INFO: Couldn't find JAX-B element for class java.lang.String

2 个答案:

答案 0 :(得分:7)

我遇到同样的问题,球衣和灰熊总是得到同样的错误。经过2周的研究,似乎这个问题与CORS(跨域)困难有关。

对我有用的解决方案是一个过滤器,它为响应头提供了一些额外的信息:

    import com.sun.jersey.spi.container.ContainerRequest;
    import com.sun.jersey.spi.container.ContainerResponse;
    import com.sun.jersey.spi.container.ContainerResponseFilter;

    class CORSFilter implements ContainerResponseFilter {

        @Override
        public ContainerResponse filter(ContainerRequest request, ContainerResponse response) {
            // instead of "*" you should provide a specific domain name for security reasons
            response.getHttpHeaders().add("Access-Control-Allow-Origin", "*");
            response.getHttpHeaders().add("Access-Control-Allow-Methods", "PUT, GET, POST, DELETE, OPTIONS");
            response.getHttpHeaders().add("Access-Control-Allow-Headers", "Content-Type");
            return response;
        }
    }

将过滤器介绍给灰熊:

    ...
    ResourceConfig rc = new ClasspathResourceConfig("my.resource.package");
    rc.getContainerResponseFilters().add(new CORSFilter());
    return GrizzlyServerFactory.createHttpServer("http://base_uri", rc);
    ...

也许你可以把这个用于tomcat。

答案 1 :(得分:2)

如果您使用的是Glassfish服务器,则需要将com.sun.enterprise.overrideablejavaxpackages设置为JVM。此外还有一个主题:

MultivaluedMap exception

希望这会对你有所帮助。