我正在为Android制作秒表应用程序。我有一个启动和停止按钮。我的问题是时间越来越快。我哪里出错了。贝娄是代码:
final Runnable updater = new Runnable() {
public void run() {
if (startIsPressed) {
time = SystemClock.elapsedRealtime() - initStart + startPointTime;
startPointTime = time;
} else {
time = startPointTime;
}
hh = time / 3600000;
hours.setText("" + formatter.format(hh));
time = time - hh * 3600000;
mm = time / 60000;
minutes.setText("" + formatter.format(mm));
time = time - mm * 60000;
ss = time / 1000;
seconds.setText("" + formatter.format(ss));
time = time - ss * 1000;
millis.setText("" + formatter.format(time / 10));
handler.postDelayed(this, 30);
}
};
startBtn.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
if (!startIsPressed) {
startIsPressed = true;
startBtn.setText(R.string.stop);
initStart = SystemClock.elapsedRealtime();
handler.post(updater);
} else {
startIsPressed = false;
startBtn.setText(R.string.start);
handler.post(updater);
}
}
});
}
答案 0 :(得分:1)
正如文档所述postDelayed导致Runnable r被添加到消息队列中,在指定的时间量过后运行。每1秒更新一次计时器: 使用
handler.postDelayed(this, 100); //100 milliseconds refresh rate
而不是
handler.postDelayed(this, 30); //30 milliseconds refresh rate
并查看秒表逻辑here