Question

我们称这个表为terms_relation：

+---------+----------+-------------+------------+------------+--+
| term_id | taxonomy | description | created_at | updated_at |  |
+---------+----------+-------------+------------+------------+--+
|       1 | categ    | non         | 3434343434 |   34343433 |  |
|       2 | categ    | non         | 3434343434 | 3434343434 |  |
|       3 | tag      | non         | 3434343434 | 3434343434 |  |
|       4 | tag      | non         | 3434343434 | 3434343434 |  |
+---------+----------+-------------+------------+------------+--+

这是表terms：

+----+-------------+-------------+
| id |    name     |    slug     |
+----+-------------+-------------+
|  1 | hello       | hello       |
|  2 | how are you | how-are-you |
|  3 | tutorial    | tutorial    |
|  4 | the end     | the-end     |
+----+-------------+-------------+

如何选择表terms和表terms_relation中表terms_relation中的分类法为categ的所有行？我是否需要两个查询，或者我可以使用join语句？

Answer 1

试试这个（子查询）：

SELECT * FROM terms WHERE id IN 
   (SELECT term_id FROM terms_relation WHERE taxonomy = "categ")

或者你可以试试这个（加入）：

SELECT t.* FROM terms AS t 
   INNER JOIN terms_relation AS tr 
   ON t.id = tr.term_id AND tr.taxonomy = "categ"

如果您想接收两个表中的所有字段：

SELECT t.id, t.name, t.slug, tr.description, tr.created_at, tr.updated_at 
  FROM terms AS t 
   INNER JOIN terms_relation AS tr 
   ON t.id = tr.term_id AND tr.taxonomy = "categ"

Answer 2

您可以使用子查询：

SELECT *
FROM terms
WHERE id IN (SELECT term_id FROM terms_relation WHERE taxonomy='categ');

如果您需要显示两个表中的所有列：

SELECT t.*, tr.*
FROM terms t, terms_relation tr
WHERE t.id = tr.term_id
AND tr.taxonomy='categ'

Answer 3

SELECT terms.*
FROM terms JOIN terms_relation ON id=term_id
WHERE taxonomy='categ'

从另一个表中选择带有id的行

3 个答案: