Question

任何人都可以通过显示用于计算三个表总计费用的创建过程语句来帮助我吗？以下是表格及其数据..

TABLE_1

accountno   shipername   shiperaddress   Executivename
   001      john         123, London          Paul
   002      Robi         127, China           Soma

TABLE_2

Executivename shipername shiperaddress accountno currentamount anotheramount    
   paul          john     123,london     001         10500       12000
   soma          robi     127,china      002         11000        6800

TABLE_3

accountno    Date        ReceivedAmount    MoneyReceiptNo
   001       1/1/2012       6500              G 256412
   002       1/2/2012       5200              D 246521

我要提到的是，总费用将计算为

(currentamount + anotheramount) - receivedamount

我尝试通过以下存储过程执行此操作。

CREATE PROCEDURE [dbo].[rptexetotaldues] @Executivename varchar(20) 
AS BEGIN
    select 
        table_1.Executivename, 
        sum(table_2.currentamount + table_2.anotheramount
             - table_3.receivedamount ) as TotalDues 
    from 
        table_1 
    full join 
        table_2 on table_1.accountno = table_2.accountno 
    join 
        table_3 on table_3.accountno = table_1.accountno 
    where 
        table_1.Executivename = @Executivename 
    group by 
        table_1.Executivename
end

但这不起作用。请有人帮帮我

Answer 1

你的样本为我工作。我唯一改变的是“日期”转换。我强烈建议避免使用“日期”作为列名。我也改变了一些别名，但那应该是好的。我认为@Gordon Linoff是对的 - 你可能会遇到NULLS的问题。

DECLARE @table_1 TABLE (accountno char(5), shipername char(20), shiperaddress char(40), Executivename varchar(20))
INSERT INTO @table_1 VALUES ('001', 'john', '123, London', 'Paul')
INSERT INTO @table_1 VALUES ('002','Robi','127, China','Soma')

DECLARE @table_2 TABLE (Executivename varchar(20), shipername char(20), shiperaddress char(40),
                        accountno char(20), currentamount decimal(10,2), anotheramount decimal(10,2))

INSERT INTO @table_2 VALUES ('paul', 'john','123,london','001',10500, 12000)
INSERT INTO @table_2 VALUES ('soma', 'robi', '127,china', '002', 11000, 6800)

DECLARE @table_3 TABLE(accountno char(20), tranDate datetime, ReceivedAmount decimal(10,2), MoneyReceiptNo char(10))
INSERT INTO @table_3 VALUES ('001', '1/1/2012', 6500, 'G 256412')
INSERT INTO @table_3 VALUES ('002', '1/2/2012', 5200,'D 246521')


DECLARE @Executivename varchar(20) 

--SET @Executivename = 'Paul'
SET @Executivename = 'Soma'

    select 
        tb1.Executivename, 
        sum(tb2.currentamount + tb2.anotheramount - tb3.receivedamount ) as TotalDues 
    from 
        @table_1 tb1
        full join @table_2 tb2 on tb1.accountno = tb2.accountno 
        join @table_3 tb3 on tb3.accountno = tb1.accountno 
    where 
        tb1.Executivename=@Executivename group by tb1.Executivename

以下是我的结果：

Executivename   TotalDues
Soma    12600.00

Answer 2

我可以想到两个问题。首先是帐号在表1或表2中重复。这将添加额外的行。

第二个是表3中有些行不在表2中。这意味着sum中的加法是NULL，因为其中一个值为NULL。您可以通过以下方式之一解决此问题：

    sum(table_2.currentamount) + sum(table_2.anotheramount) - sum(table_3.receivedamount)

或

    sum(coalesce(table_2.currentamount, 0.0) + coalesce(table_2.anotheramount, 0.0) - coalesce(table_3.receivedamount, 0.0) ) as TotalDues

Answer 3

我认为它作为UNION查询会更简单，例如：

CREATE PROCEDURE [dbo].[rptexetotaldues] @Executivename varchar(20) 
AS BEGIN

SELECT SUB.ACCOUNTNO, SUM(SUB.DUE) AS TOTALDUE FROM 
  (SELECT ACCOUNTNO
        , CURRENTAMOUNT AS DUE
   FROM TABLE_2
   INNER JOIN TABLE_1 -- WILL ONLY WORK IF ACCOUNTNO IS UNIQUE WITHIN TABLE_1
   ON TABLE_1.ACCOUNTNO = TABLE2.ACCOUNTNO
   WHERE TABLE_1.EXECUTIVENAME = @Executivename

   UNION ALL

   SELECT ACCOUNTNO
        , ANOTHERAMOUNT AS DUE
   FROM TABLE_2
   INNER JOIN TABLE_1 
   ON TABLE_1.ACCOUNTNO = TABLE2.ACCOUNTNO
   WHERE TABLE_1.EXECUTIVENAME = @Executivename

   UNION ALL

   SELECT ACCOUNTNO
        , -RECEIVEDAMOUNT AS DUE -- NOTE NEGATIVE SIGN
   FROM TABLE 3
   INNER JOIN TABLE_1 
   ON TABLE_1.ACCOUNTNO = TABLE3.ACCOUNTNO
   WHERE TABLE_1.EXECUTIVENAME = @Executivename
   ) SUB

GROUP BY SUB.ACC

如何创建用于计算总会费的sql程序

3 个答案: