我尝试了许多不同的方法来获取http响应但总是得到消息null。我尝试过使用chrome附带的Advance Rest Client工具。在那我得到了成功的回应。我不知道我在哪里做错了。
try {
String urlParameters = "id=userid&password=password&device=android";
URL url = new URL("my url");
HttpURLConnection urlConnection = (HttpURLConnection) url
.openConnection();
urlConnection.setRequestMethod("POST");
urlConnection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
urlConnection.setRequestProperty("Content-Length",
"" + Integer.toString(urlParameters.getBytes().length));
urlConnection.setRequestProperty("Content-Language", "en-US");
urlConnection.setUseCaches(false);
urlConnection.setDoInput(true);
urlConnection.setDoOutput(true);
OutputStream outputStream = urlConnection.getOutputStream();
outputStream.write(urlParameters.getBytes());
outputStream.close();
int responseCode = urlConnection.getResponseCode();
if (responseCode == HttpURLConnection.HTTP_OK) {
InputStream in = urlConnection.getInputStream();
resultstring = convertinputStreamToString(in);
Log.d("Result String-------->", resultstring);
}
} catch (Exception e) {
e.printStackTrace();
}
我附上了截图,我得到了结果:成功 但是在上面的代码中我得到了结果:失败
我也尝试过使用HttpClient和HttpPost的代码。但这也是一项工作
try {
HttpClient client = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(
"my url");
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/x-www-form-urlencoded");
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(3);
nameValuePairs.add(new BasicNameValuePair("id", "userid"));
nameValuePairs.add(new BasicNameValuePair("password", "password"));
nameValuePairs.add(new BasicNameValuePair("device", "android"));
// httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
UrlEncodedFormEntity se = new UrlEncodedFormEntity(nameValuePairs);
se.setContentType("application/x-www-form-urlencoded");
httpPost.setEntity(se);
httpPost.getParams().setBooleanParameter(
"http.protocol.expect-continue", false);
HttpResponse response = client.execute(httpPost);
String responseAsText = EntityUtils.toString(response.getEntity());
Log.d("Result String-------->", responseAsText);
} catch (Exception e) {
e.printStackTrace();
}
请帮帮我。我几乎尝试了一切。
答案 0 :(得分:-1)
HttpClient localHttpClient = this.app2.getHttpClient();
HttpPost localHttpPost = new HttpPost("yourURL.com");
localHttpPost.setEntity(new UrlEncodedFormEntity(myArrayList));
InputStream localInputStream = localHttpClient.execute(localHttpPost).getEntity().getContent();
尝试这样的事情。 您必须将响应作为输入流读取,然后在返回结果后继续工作。
另外,请务必检查服务器,因为它可能没有按预期返回响应。