我有两个时间值,如下所示
$time = 06:58:00;
$time2 = 00:40:00;
我这样做是为了计算特定用户的约会和可用时间 所以我试着用这种方式
$max_date=abs(strtotime($time) + strtotime($time2));
但它返回$ max_date = 2673452280 任何建议请
答案 0 :(得分:24)
此代码示例需要$time
中的小时,并将$time2
中的小时添加到其中
例如:time = 06:58:00,time2 = 00:40:00,result = 07:38:00
$time = "06:58:00";
$time2 = "00:40:00";
$secs = strtotime($time2)-strtotime("00:00:00");
$result = date("H:i:s",strtotime($time)+$secs);
答案 1 :(得分:5)
使用此功能......
function sum_the_time($time1, $time2) {
$times = array($time1, $time2);
$seconds = 0;
foreach ($times as $time)
{
list($hour,$minute,$second) = explode(':', $time);
$seconds += $hour*3600;
$seconds += $minute*60;
$seconds += $second;
}
$hours = floor($seconds/3600);
$seconds -= $hours*3600;
$minutes = floor($seconds/60);
$seconds -= $minutes*60;
if($seconds < 9)
{
$seconds = "0".$seconds;
}
if($minutes < 9)
{
$minutes = "0".$minutes;
}
if($hours < 9)
{
$hours = "0".$hours;
}
return "{$hours}:{$minutes}:{$seconds}";
}
答案 2 :(得分:2)
如果你以前从数据库构建那些时间字符串,你可能想要将它们重建为:
$time = "00:06:58";
$time2 = "40 minutes";
$timestamp = strtotime($time." +".$time2);
$endTime = date("d.m.Y H:i:s", $timestamp);
答案 3 :(得分:1)
strtotime函数将完整日期作为参数,有效格式如下: http://www.php.net/manual/en/datetime.formats.php
的功能的在线PHP手册中看到答案 4 :(得分:1)
使用php添加两次的最简单方法是:
1)将时间从H:i:s(例如08:15:40)格式转换为秒
2)对第二次值ref做同样的步骤:步骤1
3)添加转换后的值并将其存储为php变量
4)现在将总数(以秒为单位)转换为H:i:s
它适用于我。
PHP脚本:
$str_time ="08:04:40";
$str_time = preg_replace("/^([\d]{1,2})\:([\d]{2})$/", "00:$1:$2", $str_time);
sscanf($str_time, "%d:%d:%d", $hours, $minutes, $seconds);
$hrs_old_seconds = $hours * 3600 + $minutes * 60 + $seconds;
$str_time ="02:10:22";
$str_time = preg_replace("/^([\d]{1,2})\:([\d]{2})$/", "00:$1:$2", $str_time);
sscanf($str_time, "%d:%d:%d", $hours, $minutes, $seconds);
$hrs_toadd_seconds = $hours * 3600 + $minutes * 60 + $seconds;
$hrs_old_int1 = $hrs_old_seconds + $hrs_toadd_seconds;
echo $Total=gmdate("H:i:s", $hrs_old_int1);
结果=:10:15:02
答案 5 :(得分:0)
Anudeep's solution非常适合我的用例,但我还需要能够增加负数时间。这是他的代码的略作修改的版本,用于获取并返回负时间字符串(例如“ -01:01:01”):
public static function sum_the_times($time1, $time2)
{
$times = array($time1, $time2);
$seconds = 0;
$negative = false;
foreach ($times as $time) {
list($hour,$minute,$second) = explode(':', $time);
if(substr($hour,0,1) == '-'){
$seconds -= substr($hour,1)*3600;
$seconds -= $minute*60;
$seconds -= $second;
} else {
$seconds += $hour*3600;
$seconds += $minute*60;
$seconds += $second;
}
}
if (substr($seconds, 0, 1) == '-') {
$negative = true;
$seconds = ($seconds * -1);
}
$hours = floor($seconds/3600);
$seconds -= $hours*3600;
$minutes = floor($seconds/60);
$seconds -= $minutes*60;
if ($seconds < 9) {
$seconds = "0".$seconds;
}
if ($minutes < 9) {
$minutes = "0".$minutes;
}
if ($hours < 9) {
$hours = "0".$hours;
}
return ($negative ? "-" : "")."{$hours}:{$minutes}:{$seconds}";
}
答案 6 :(得分:0)
您可以尝试
$time = "04:00:00";
$time2 = "03:30:00";
$result = date("H:i:s",strtotime($time)+strtotime($time2));
echo $result;
它提供输出07:30:00,但在不同版本的操作系统中有时无法正常工作。如果您想获取时间总和,则可以使用此代码
<?php
function CalculateTime($time1, $time2) {
$time1 = date('H:i:s',strtotime($time1));
$time2 = date('H:i:s',strtotime($time2));
$times = array($time1, $time2);
$seconds = 0;
foreach ($times as $time)
{
list($hour,$minute,$second) = explode(':', $time);
$seconds += $hour*3600;
$seconds += $minute*60;
$seconds += $second;
}
$hours = floor($seconds/3600);
$seconds -= $hours*3600;
$minutes = floor($seconds/60);
$seconds -= $minutes*60;
if($seconds < 9)
{
$seconds = "0".$seconds;
}
if($minutes < 9)
{
$minutes = "0".$minutes;
}
if($hours < 9)
{
$hours = "0".$hours;
}
return "{$hours}:{$minutes}:{$seconds}";
}
$time1= '23:32:05';
$time2 = '01:29';
echo CalculateTime($time1,$time2);
?>
在第二个代码中,您可以按小时:分钟或小时:分钟:秒发送时间。该代码接受两种格式,因为它会自动转换时间