我想从列表中删除一个对象,同时我想为用户设置一个淡出动画...
remove函数创建一个Thread
,在线程中我尝试启动动画,但我得到了这个例外:
android.view.ViewRoot$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views.
关于活动:
private Animation animation;
private AnimationListener al;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.test);
animation = AnimationUtils.loadAnimation(this, R.anim.fade_out);
al = new AnimationListener() {
public void onAnimationStart(Animation animation) {
// do nothing
}
public void onAnimationRepeat(Animation animation) {
// do nothing
}
public void onAnimationEnd(Animation animation) {
TableRow tr = (TableRow) findViewById(R.id.test);
tr.setVisibility(View.GONE);
}
};
animation.setAnimationListener(al);
animation.reset();
}
当用户按下删除图标时,他将到达此处:
public void remove(View v) {
RemoveF rf = new RemoveF();
rf.start();
}
我的Tread从这里开始:
class RemoveF extends Thread {
private boolean running;
public void run() {
running = true;
try {
do {
//business logic goes here
TableRow tr = (TableRow) findViewById(R.id.test);
tr.setAnimation(animation);
tr.startAnimation(animation);
stopRunning();
try {
Thread.sleep(1000);
} catch (InterruptedException ie) {
// do nothing
}
} while (running);
} catch (Exception e) {
Log.e("RemoveF", "Exception", e);
}
}
public void stopRunning() {
running = false;
}
}
我知道如何解决它? 感谢
答案 0 :(得分:2)
此处TableRow tr = (TableRow) findViewById(R.id.test);
您正试图从另一个线程访问UI元素。
使用runOnUiThread
或Handler
从线程