当我尝试构建和分析事物时,下面的代码片段会泄漏。
这段代码有什么问题,请告诉我
- ( NSString *) getSubCategoryTitle:(NSString*)dbPath:(NSString*)ID{
NSString *subCategoryTitle;
if (sqlite3_open([dbPath UTF8String], &database) == SQLITE_OK)
{
NSString *selectSQL = [NSString stringWithFormat: @"select sub_category_name from sub_categories where id = %@",ID];
NSLog(@"%@ I am creashes here", selectSQL);
const char *sql_query_stmt = [selectSQL UTF8String];
sqlite3_stmt *selectstmt;
if(sqlite3_prepare_v2(database, sql_query_stmt, -1, &selectstmt, NULL) == SQLITE_OK)
{
while(sqlite3_step(selectstmt) == SQLITE_ROW)
{
subCategoryTitle = [[NSString alloc] initWithUTF8String:
(const char *) sqlite3_column_text(selectstmt, 0)];
}
}
sqlite3_finalize(selectstmt);
}
sqlite3_close(database);
return [subCategoryTitle autorelease];
}
答案 0 :(得分:2)
您在循环中将实例分配到subCategoryTitle
,但不释放先前的分配。
subCategoryTitle = [[NSString alloc] initWithUTF8String:
(const char *) sqlite3_column_text(selectstmt, 0)];
要么(自动)释放它,要么直接转到最后一行,并避免这样做,因为它没有多大意义。
仅创建最后一个对象的示例:
char * col_text = NULL;
while(sqlite3_step(selectstmt) == SQLITE_ROW)
{
col_text = sqlite3_column_text(selectstmt, 0);
}
if (col_text != NULL)
{
subCategoryTitle = [[NSString alloc] initWithUTF8String:col_text];
}