Dim n, front, rear As Integer
Dim x As Integer
Dim arr() As Integer
Public Function init()
n = InputBox("Enter size :")
ReDim arr(n) As Integer
front = 0
rear = -1
End Function
Public Function insert(x As Integer)
If rear = n-1 Then
MsgBox "queue FULL !!!", vbOKOnly, "QUEUE"
Else
rear = rear + 1
arr(rear) = x
MsgBox x, vbOKOnly, "INSERTED"
End If
End Function
Public Function delete() As Integer
If rear + 1 = front Then
MsgBox "queue Empty !!!", vbOKOnly, "QUEUE"
Else
x = arr(front)
front = front + 1
Return x
End If
End Function
Private Sub inser_Click()
If rear < n Then
x = InputBox("Enter element :")
Call insert(x)
Else
MsgBox "queue FULL !!!", vbOKOnly, "QUEUE"
End If
End Sub
Private Sub del_Click()
x = delete()
MsgBox x, vbOKOnly, "DELETED"
End Sub
Private Sub Exit_Click()
End
End Sub
Private Sub Form_Load()
Call init
End Sub
这是我在VB6中的代码。
我在insert
行的Return x
函数中收到错误,其中显示“编译错误预期:结束语句”
还有一个错误是每当我尝试删除队列中的元素时,它会显示“0 DELETED”
答案 0 :(得分:6)
您尝试使用Return语句从函数返回值,该语句在VB6中无效。在VB6中,通过将返回值赋给函数名称来返回Function的值。
所以对于你的delete
函数,你会写这个:
Public Function delete() As Integer
If rear + 1 = front Then
MsgBox "queue Empty !!!", vbOKOnly, "QUEUE"
Else
x = arr(front)
front = front + 1
delete = x ' <-- returning x here.
End If
End Function
看一下你的其他函数,它们根本没有明确地返回值。
查看this可能会有所帮助,它提供了Subs和Functions在VB6中如何工作的概述。