有没有办法检测可观察的嵌套结构的任何元素是否已经改变?

时间:2012-05-10 16:05:10

标签: javascript knockout.js

如果viewModel.data()的任何可观察元素发生了变化,是否有一个发射器可以触发,或者我是否需要遍历并订阅每个独立的observable?

data: ko.observable([
      {
        name: "Chart Position",
        fields: ko.observableArray([
          {name: "marginBottom", type: "percOrNumber", value: ko.observable(), valueType: ko.observable()},
          {name: "marginLeft", type: "percOrNumber", value: ko.observable(), valueType: ko.observable()},
          {name: "marginRight", type: "percOrNumber", value: ko.observable(), valueType: ko.observable()},
          {name: "marginTop", type: "percOrNumber", value: ko.observable(), valueType: ko.observable()}
        ])
      }
    ]),

1 个答案:

答案 0 :(得分:2)

您可以使用计算的observable同时“订阅”多个observable。在计算的可观察量的评估中访问其值的任何可观察量将成为依赖性。

所以,你可以这样做:

ko.computed(function() {
    this.one();  //just accessing the value for a dependency
    this.two();  //doesn't matter if we actually use the value
    this.three();

    //run some code here or if you have a reference to this computed observable, then you can even do a manual subscription against it.
}, vm);

如果要订阅某个对象图中的所有可观察对象,那么一种简单的方法就是使用ko.toJS。在您的示例中,您可能希望这样做:

ko.computed(function() {
   ko.toJS(vm.data);  //will create dependencies on all observables inside "data"

   //run some code
}, vm.data);