我必须找到此代码的控制流图和圈复杂度,然后建议一些白盒测试用例和黑盒测试用例。但我无法为代码制作CFG。
也会对测试用例提供一些帮助。
private void downShift(int index)
{
// index of "child", which will be either index * 2 or index * 2 + 1
int childIndex;
// temp storage for item at index where shifting begins
Comparable temp = theItems[index];
// shift items, as needed
while (index * 2 <= theSize)
{
// set childIndex to "left" child
childIndex = index * 2;
// move to "right" child if "right" child < "left" child
if (childIndex != theSize && theItems[childIndex + 1].compareTo(theItems[childIndex]) < 0)
childIndex++;
if (theItems[childIndex].compareTo(temp) < 0)
{
// shift "child" down if child < temp
theItems[index] = theItems[childIndex];
}
else
{
// shifting complete
break;
}
// increment index
index = childIndex;
}
// position item that was originally at index where shifting began
theItems[index] = temp;
}
答案 0 :(得分:1)
这里的基本圈复杂度是4:而+ if + if + 1.如果你考虑扩展的圈复杂度,就像通过理解或CMTJava所做的那样,你还需要为联合添加1,所以它将是5.无条件控制语句(如break
)不会影响圈复杂度值。