Question

这已经涉及四个INNER JOIN和一个LEFT JOIN，但我不知道如何引用一个类似于LEFT JOIN表的表。

这是我当前的查询，它可以按照

的方式工作

 SELECT xp.productid, xp.product, xc.classid, xco.optionid, xco.option_name, xiW.id, xiW.image_path, count(xvi.variantid) as cnt
    FROM xcart_products xp
    INNER JOIN xcart_variants xv ON xp.productid = xv.productid
    INNER JOIN xcart_variant_items xvi ON xv.variantid = xvi.variantid
    INNER JOIN xcart_class_options xco ON xvi.optionid = xco.optionid
    INNER JOIN xcart_classes xc ON xco.classid = xc.classid AND xc.class = 'COLOR'
    LEFT JOIN xcart_images_W xiW ON xiW.id = xvi.variantid
    GROUP BY xco.optionid
    ORDER by xp.product DESC

基本上每个产品都有一个类和一个变体，然后每个类都有类选项，每个变体都有变体项。变体有自己的变体图像，每个类都有自己的“详细”图像（xcart_images_D）。截至目前，我正在引用变体图像，但我想要做的不是计算xvi.variantid，而是想计算每个optionid有多少详细图像。

我有一个查询会执行此操作，但遗憾的是我无法使用此查询来提取xcart_images_W。该查询是belo

 SELECT xp.productid, xp.product, xc.classid, xco.optionid, xco.option_name, xiD.image_path, xiD.path_on_server, count(xiD.optionid) as cnt
    FROM xcart_products xp
    INNER JOIN xcart_classes xc ON xp.productid = xc.productid AND xc.class = 'Color'
    INNER JOIN xcart_class_options xco ON xc.classid = xco.classid
    LEFT JOIN xcart_images_D xiD ON xiD.optionid = xco.optionid
    GROUP BY xp.product, xco.optionid
    ORDER by xp.product DESC

是否可以引用这两个表或使用外键使其无法这样做？

下面我提供了表结构。

+ xcart_products
    - productid*
    - product
+ xcart_variants
    - variantid*
    - productid (xcart_products.productid)
+ xcart_variant_items [bridge table]
    - optionid*
    - variantid (xcart_variants.variantid)
+ xcart_classes
    - classid*
    - productid (xcart_products.productid)
    - class
+ xcart_class_options
    - optionid*
    - option_name
    - classid (xcart_classes.classid)
+ xcart_images_W
    - imageid*
    - id (xcart_variants.variantid)
    - image_path
+ xcart_images_D
    - imageid* [not relational with xcart_images_W.imageid]
    - id (xcart_products.productid)
    - optionid (xcart_class_options.optionid)
    - image_path

* Primary Key
() relational data
[] notes

目前工作但是凌乱的查询。我该如何清理？

 SELECT xp.productid, xp.product, xc.classid, xco.optionid, xco.option_name, xiW.id, xiW.image_path
 FROM xcart_products xp
 INNER JOIN xcart_variants xv ON xp.productid = xv.productid
 INNER JOIN xcart_variant_items xvi ON xv.variantid = xvi.variantid
 INNER JOIN xcart_class_options xco ON xvi.optionid = xco.optionid
 INNER JOIN xcart_classes xc ON xco.classid = xc.classid AND xc.class = 'COLOR'
 LEFT JOIN xcart_images_W xiW ON xiW.id = xvi.variantid
 LEFT JOIN (
 SELECT COUNT(xiD.optionid) as dCount 
    FROM xcart_products xp2
    INNER JOIN xcart_classes xc2 ON xp2.productid = xc2.productid AND xc2.class = 'Color'
    INNER JOIN xcart_class_options xco2 ON xc2.classid = xco2.classid
    LEFT JOIN xcart_images_D xiD ON xiD.optionid = xco2.optionid
 ) ON xiW.id = xvi.variantid
 GROUP BY xco.optionid
 ORDER by xp.product DESC

Answer 1

在您提供表格定义之前，这一点并不完全清楚。您是否尝试在第一个查询中用count（xiW.id）替换count（xvi.variantid）？

更新

SELECT xp.productid, xp.product, xc.classid, xco.optionid, xco.option_name, xiW.id, xiW.image_path, count(xvi.variantid) as cnt
FROM xcart_products xp
INNER JOIN xcart_variants xv ON xp.productid = xv.productid
INNER JOIN xcart_variant_items xvi ON xv.variantid = xvi.variantid
INNER JOIN xcart_class_options xco ON xvi.optionid = xco.optionid
INNER JOIN xcart_classes xc ON xco.classid = xc.classid AND xc.class = 'COLOR'
LEFT JOIN (
   SELECT COUNT(xiD.id) as Dcount 
   FROM xcart_images_D xiD 
   INNER JOIN xcart_images_W xiW ON xiW.column = xiD.column /*please update accordingly */
 ) ON xiW.id = xvi.variantid 
GROUP BY xco.optionid
ORDER by xp.product DESC

再次更新：

SELECT xp.productid, xp.product, xc.classid, xco.optionid, xco.option_name, xiW.id, xiW.image_path, count(xvi.variantid) as cnt, xiD.totalD
FROM xcart_products xp
INNER JOIN xcart_variants xv ON xp.productid = xv.productid
INNER JOIN xcart_variant_items xvi ON xv.variantid = xvi.variantid
INNER JOIN xcart_class_options xco ON xvi.optionid = xco.optionid
INNER JOIN xcart_classes xc ON xco.classid = xc.classid AND xc.class = 'COLOR'
LEFT JOIN (
   SELECT count(xiD.id) as totalD, xiD.optionid FROM xcart_images_D xiD WHERE xiD.optionid = xvi.optionid
) ON xiD.optionid = xvi.optionid
GROUP BY xco.optionid
ORDER by xp.product DESC

可以使用一个查询引用两个特定表

1 个答案: