Question

>          cycleNO| month |   year|  start date |    close date         |state | prv month  | next mnt 
>             1      4        2012    1/4/2012     30/4/2012 23:59:59      1       3                5
>             1      5        2012    1/5/2012     31/5/2012 23:59:59      0       4                6  
>             1      6        2012    1/6/2012     30/6/2012 23:59:59      0       5                7  
>             1      7        2012    1/7/2012     31/7/2012 23:59:59      0       6                8
>             2      4        2012    1/4/2012     30/4/2012 23:59:59      1       3                5
>             2      5        2012    1/5/2012     31/5/2012 23:59:59      0       4                6  
>             2      6        2012    1/6/2012     30/6/2012 23:59:59      0       5                7  
>             2      7        2012    1/7/2012     31/7/2012 23:59:59      0       6                8

我有一个表（cycle_set），如上所述，想要获取（cycleNO，月，年，开始日期，结束日期）条件，其中state = 0和start-close日期，其中包含系统日期也是立即下个月，州= 0。

输出应为：

cycleNO | month | year | start date | close date 
1      5        2012    1/5/2012     31/5/2012 23:59:59
1      6        2012    1/6/2012     30/6/2012 23:59:59
2      5        2012    1/5/2012     31/5/2012 23:59:59
2      6        2012    1/6/2012     30/6/2012 23:59:59

Answer 1

SELECT cycleNO,month,year,start_date,close_date FROM cycle_set
WHERE state=0
AND MONTH(start_date) = (SELECT month FROM cycle_set WHERE state=0 AND...)
AND MONTH(close_date) = (SELECT month FROM cycle_set WHERE state=0 AND...)

问题是，您无法选择下一个结果月份。这两个子选择中WHERE子句的内容是什么？

如果您提取所有数据，然后使用PHP或其他任何数据进行处理，那将会容易得多。

Answer 2

select cycleNO,month,year,start_date,close_date 
FROM cycle_set
WHERE state=0 and sysdate between start_date and close_date

更新：如果您想同时获得当前和下个月：

select cycleNO, month, year, start_date, close_date 
FROM cycle_set
WHERE state=0 
   and ( sysdate between start_date and close_date or --current month
         sysdate between add_months(start_date,-1)  and close_date --next_month
        )

Answer 3

假设您有一个数据集（如示例所示）：

    SELECT  cycleno,month,year,start_date,close_date 
      FROM  cycle_set
     WHERE  state=0 
       AND  (   month = EXTRACT(month FROM sysdate) 
             OR month = EXTRACT(month FROM sysdate)+1
            )
  ORDER BY  cycleno, month, year, start_date

获取具有系统日期和状态的行

3 个答案: