如果我有一个IP地址范围(CIDR表示法),我需要知道某个任意IP地址是否在该范围内 - 两者都表示为字符串 - 用C#执行此操作的最简单方法是什么?
示例:
192.168.168.100/24
,要检查的IP:192.168.168.200
fe80::202:b3ff:fe1e:8329/24
,要检查的IP:2001:db8::
答案 0 :(得分:11)
这是一个简单的课程:
public class IPSubnet
{
private readonly byte[] _address;
private readonly int _prefixLength;
public IPSubnet(string value)
{
if (value == null)
throw new ArgumentNullException("value");
string[] parts = value.Split('/');
if (parts.Length != 2)
throw new ArgumentException("Invalid CIDR notation.", "value");
_address = IPAddress.Parse(parts[0]).GetAddressBytes();
_prefixLength = Convert.ToInt32(parts[1], 10);
}
public bool Contains(string address)
{
return this.Contains(IPAddress.Parse(address).GetAddressBytes());
}
public bool Contains(byte[] address)
{
if (address == null)
throw new ArgumentNullException("address");
if (address.Length != _address.Length)
return false; // IPv4/IPv6 mismatch
int index = 0;
int bits = _prefixLength;
for (; bits >= 8; bits -= 8)
{
if (address[index] != _address[index])
return false;
++index;
}
if (bits > 0)
{
int mask = (byte)~(255 >> bits);
if ((address[index] & mask) != (_address[index] & mask))
return false;
}
return true;
}
}
样本用法:
Console.WriteLine(new IPSubnet("192.168.168.100/24").Contains("192.168.168.200")); // True
Console.WriteLine(new IPSubnet("fe80::202:b3ff:fe1e:8329/24").Contains("2001:db8::")); // False
此类将所有IPv4地址视为与所有IPv6地址不同,不会尝试在IPv4和IPv6之间进行转换。
答案 1 :(得分:2)
我不打算为你编写代码,但是:
应该足以让你入门。
祝你好运答案 2 :(得分:1)
我建议使用IPNetwork Library https://github.com/lduchosal/ipnetwork。 从版本2开始,它也支持IPv4和IPv6。
<强>的IPv6 强>
IPNetwork ipnetwork = IPNetwork.Parse("fe80::202:b3ff:fe1e:8329/24");
IPAddress ipaddress = IPAddress.Parse("2001:db8::");
IPAddress ipaddress2 = IPAddress.Parse("fe80::202:b3ff:fe1e:1");
bool contains1 = IPNetwork.Contains(ipnetwork, ipaddress);
bool contains2 = IPNetwork.Contains(ipnetwork, ipaddress2);
Console.WriteLine("{0} contains {1} : {2}", ipnetwork, ipaddress, contains1);
Console.WriteLine("{0} contains {1} : {2}", ipnetwork, ipaddress2, contains2);
输出
fe80::/24 contains 2001:db8:: : False
fe80::/24 contains fe80::202:b3ff:fe1e:1 : True
<强>的IPv4 强>
IPNetwork ipnetwork = IPNetwork.Parse("192.168.168.100/24");
IPAddress ipaddress = IPAddress.Parse("192.168.168.200");
IPAddress ipaddress2 = IPAddress.Parse("192.168.0.200");
bool contains1 = IPNetwork.Contains(ipnetwork, ipaddress);
bool contains2 = IPNetwork.Contains(ipnetwork, ipaddress2);
Console.WriteLine("{0} contains {1} : {2}", ipnetwork, ipaddress, contains1);
Console.WriteLine("{0} contains {1} : {2}", ipnetwork, ipaddress2, contains2);
输出
192.168.168.0/24 contains 192.168.168.200 : True
192.168.168.0/24 contains 192.168.0.200 : False
玩得开心!