Question

我有一个表单，可以将信息发送到mysql数据库。错误消息和确认在单独的div中显示在表单的右侧，因此表单操作需要将用户发送到同一页面。我正在回应用户键入的字段，以防他们需要根据出现的错误消息编辑内容。但是，如果表单提交正确，我怎么能这样做，所以php不会在表单中回显？

<?php

$submit = filter_input(INPUT_POST, 'submit');
//form data
$fullname = filter_input(INPUT_POST, 'fullname');
$email = filter_input(INPUT_POST, 'email');
$business = filter_input(INPUT_POST, 'business');
$date = date("Y-m-d");

?>

然后在其他HTML代码之后......

  <div class="wrap">
      <div id="reg">

  <form action='register.php' method='POST'>
<table>
    <tr>
        <td>
        Your full name:
        </td>
        <td>
        <input type='text' name='fullname' value='<?php echo $fullname;?>'>
        }
        </td>

    </tr>
    <tr>
        <td>
        Your email:
        </td>
        <td>
        <input type='text' name='email' value='<?php echo $email;?>'>
        </td>

    </tr>

    <tr>
        <td>
        Your business:
        </td>
        <td>
        <input type='text' name='business' value='<?php echo $business;?>'>
        </td>

    </tr>






 </table>
 </br>
 <input type='submit' name='submit' value='Register'>

</form>
 </br>       

    </div>
    <?php
 if ($submit)
  {
    //open database
  $connect=mysql_connect("localhost","root","Ryweb1994");
  mysql_select_db("phapsy");


  //check for existence
if($fullname&&$business&&$business)
{

   $queryreg = mysql_query("INSERT INTO users VALUES                           ('','$fullname','$email','$business','$date')");
    echo ("<div id='message'><p>You have been registered! We will send you an email            with login information. Thank you for your interest in Phapsy!<p></div>");

   }
else echo "Please fill in <b>all</b> fields!";

   }


  ?>
    </div>
  </div>

Answer 1

使用$submit变量包裹表单：

+ <?php if($submit) { ?>
 <div class="wrap">
  ... 
  <form action='register.php' method='POST'>
  ...
  </form>
</div>
+ <?php }; ?>

    <?php
 if ($submit)
  {
    //open database
  $connect=mysql_connect("localhost","root","Ryweb1994");
  mysql_select_db("phapsy");


  //check for existence
if($fullname&&$business&&$business)
{

   $queryreg = mysql_query("INSERT INTO users VALUES                           ('','$fullname','$email','$business','$date')");
    echo ("<div id='message'><p>You have been registered! We will send you an email            with login information. Thank you for your interest in Phapsy!<p></div>");

   }
else echo "Please fill in <b>all</b> fields!";

   }


  ?>
    </div>
  </div>

Answer 2

由于您说您正在回复确认信息，因此您显然会以某种方式测试成功输入 - 但您不会显示该代码。

像<input type='text' name='fullname' value='<?php if(!$successful){echo $fullname;} ?>'>之类的东西会这样做

Answer 3

将处理逻辑放在显示逻辑之前。

设置一个反映数据库交互是否成功的变量。

更新整个表单中的echo语句，只有在交互失败（或验证失败）时才打印一个值：

<?php $successfullyProcessed = false;

//processing logic
$successfullyProcessed = true;


<input type='text' name='fullname' value='<?php if (!successfullyProcessed) echo $fullname;?>'>

提交后以表格回复

3 个答案: