任何人都可以告诉我为什么所有Rects都会激活同一个Activity

时间:2012-05-09 11:50:50

标签: java android

* MyImage类扩展视图和实现ontouchListener * enter code here

公共类MyImage扩展了View实现的OnTouchListener {

Bitmap orignal;
Bitmap scaled;
Matrix m;
Context ctext;
ArrayList<Rect> rect;

我有四个矩形,所有矩形都用于移动 diff diff Activity         Rect rectangle0;     Rect rectangle1;     Rect rectangle2;     矩形矩形3;     矩形矩形4;     private int X_POSITION;     private int Y_POSITION;

public MyImage(Context context) {
    super(context);

    ctext = context;

}


@Override
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
    // TODO Auto-generated method stub
    super.onMeasure(widthMeasureSpec, heightMeasureSpec);

}

@Override
public View findFocus() {
    // TODO Auto-generated method stub
    return super.findFocus();
}

@Override
public boolean isPressed() {
    // TODO Auto-generated method stub
    return super.isPressed();

}

@Override
public boolean isSelected() {
    // TODO Auto-generated method stub
    return super.isSelected();

}



@Override
public boolean onTouchEvent(MotionEvent event) {


     X_POSITION = (int)event.getX();
     Y_POSITION = (int)event.getY();

    System.out.println(X_POSITION + "\t" +Y_POSITION); 

问题出现在这里我不知道为什么所有矩形都会触发相同的活动,以及如何解决这个问题,以便所有矩形能够激发差异

    switch (event.getAction()) {

    case MotionEvent.ACTION_DOWN:


        Intent i = new Intent(ctext , SelecterImage.class);
        ctext.startActivity(i);

    }

return true;

}

@Override
public void onDraw(Canvas canvas) {
    Paint paint = new Paint();

    int X_WIDTH = canvas.getWidth();
    int Y_HEIGHT = canvas.getHeight() / 2;

    System.out.println(X_WIDTH + "\n" + Y_HEIGHT);

    Paint rectanglePaint = new Paint();
    rectanglePaint.setARGB(255, 0, 0, 0);
    rectanglePaint.setStrokeWidth(2);
    rectanglePaint.setColor(Color.BLUE);

    rectangle0 = new Rect(10, 420, 60, 380);
    rectangle1 = new Rect(70, 420, 120, 380);


    rectangle2 = new Rect(130, 420, 180, 380);
    rectangle3 = new Rect(190, 420, 240, 380);
    rectangle4 = new Rect(250, 420, 300, 380);


    canvas.drawRect(rectangle0, rectanglePaint);

    canvas.drawRect(rectangle1, rectanglePaint);

    canvas.drawRect(rectangle2, rectanglePaint);

    canvas.drawRect(rectangle3, rectanglePaint);

    canvas.drawRect(rectangle4, rectanglePaint);

    scaled = Bitmap.createScaledBitmap(orignal, X_WIDTH, Y_HEIGHT, false);

    canvas.drawBitmap(scaled, 0, 0, paint);

}


void setBitmap(Bitmap bitmap) {
    // TODO Auto-generated method stub

    orignal = bitmap;

}



@Override
public boolean onTouch(View v, MotionEvent event) {
    return false;
    // TODO Auto-generated method stub




}   


}

强文

1 个答案:

答案 0 :(得分:0)

首先确保onTouchEvent正常工作(确实像你一样返回X和Y)然后

@Override 
public boolean onTouchEvent(MotionEvent event) { 


    X_POSITION = (int)event.getX(); 
    Y_POSITION = (int)event.getY(); 

    if (event.getAction == MotionEvent.ACTION_DOWN)
    {
        if (rectangle0.contains(X_POSITION,Y_POSITION))
        {
           Intent i = new Intent(ctext , Activity1.class); 
           ctext.startActivity(i); 
        }
        else if (rectangle1.contains(X_POSITION,Y_POSITION))
        {
           Intent i = new Intent(ctext , Activity2.class); 
           ctext.startActivity(i); 
        }

        ....

    } 
}