从Mysql表中获取前5位客户

Question

我有一个表'tbl_orders'，该表包含以下

order_id | customer_id | grand_total

现在我需要找出与我有更多订单的TOP 5客户

我尝试下面的查询，

"SELECT customer_id , count(customer_id) as total_orders FROM `tbl_order` group by customer_id"

但是这个查询只给了我所有的customer_id＆amp;每个客户的总数和我想获取TOP 5客户，即与我订购更多订单

Answer 1

添加到DonCallisto的答案中，您可能还希望按最多订单排序。否则你将无法获得前5名。

SELECT customer_id , count(order_id) as total_orders 
FROM `tbl_order` 
GROUP BY customer_id 
ORDER BY total_orders DESC
LIMIT 5

注意我还将count列从customer_id更改为order_id。这在功能上没有任何区别，但对于阅读代码的人来说更有意义。

Answer 2

SELECT customer_id , count(customer_id) as total_orders 
FROM `tbl_order` GROUP BY customer_id ORDER BY total_orders DESC LIMIT 5