在我的存储过程中,我遇到了以下问题 - 我该如何解决这个问题?
CREATE PROC RupeshTest(@QueID int, @Answer varchar(250)) as
BEGIN
DECLARE @STR varchar(4000)
SELECT @STR = COALESCE(@str + ';','') + AnswerText
FROM SurveyQuestionAnswerTypes
WHERE AnswerType = (SELECT AnswerType
FROM SurveyQuestions
WHERE QuestionID = CAST(@QueId AS VARCHAR(4)))
AND AnswerValue IN (REPLACE(@Answer,'^',','))
END
我跑的时候
RupeshTest 25, '2^3^5^7^8'
我收到以下错误
Msg 245,Level 16,State 1,Procedure RupeshTest,Line 4
将varchar值'2,3,5,7,8'转换为数据类型int时,转换失败。
虽然我理解了这个问题,但无法解决问题,但有些人可以告诉我如何解决它。
答案 0 :(得分:2)
这不会起作用,因为形成的最终查询是:
SELECT @STR = COALESCE(@str + ';','') + AnswerText
FROM SurveyQuestionAnswerTypes
WHERE AnswerType = (SELECT AnswerType
FROM SurveyQuestions
WHERE QuestionID = CAST(@QueId AS VARCHAR(4)))
AND AnswerValue IN ('2,3,5,7,8')
你想要这样的地方:
SELECT @STR = COALESCE(@str + ';','') + AnswerText
FROM SurveyQuestionAnswerTypes
WHERE AnswerType = (SELECT AnswerType
FROM SurveyQuestions
WHERE QuestionID = CAST(@QueId AS VARCHAR(4)))
AND AnswerValue IN (2,3,5,7,8)
我建议您创建一个UDF String_To_Table,将该字符串传递给该UDF并用于IN子句。
String_To_Table UDF:
CREATE FUNCTION [dbo].[String_To_Table]
(@string VARCHAR(4000),
@delimiter CHAR(1) = ';')
RETURNS @tbl TABLE (ord INT IDENTITY(1, 1) NOT NULL,
token VARCHAR(500)) AS
BEGIN
DECLARE @pos int,
@textpos int,
@chunklen smallint,
@tmpstr varchar(4000),
@leftover varchar(4000),
@tmpval varchar(4000)
SET @textpos = 1
SET @leftover = ''
WHILE @textpos <= datalength(@string)
BEGIN
SET @chunklen = 4000 - datalength(@leftover)
SET @tmpstr = @leftover + substring(@string, @textpos, @chunklen)
SET @textpos = @textpos + @chunklen
SET @pos = charindex(@delimiter, @tmpstr)
WHILE @pos > 0
BEGIN
SET @tmpval = ltrim(rtrim(left(@tmpstr, @pos - 1)))
INSERT @tbl (token) VALUES(@tmpval)
SET @tmpstr = substring(@tmpstr, @pos + 1, len(@tmpstr))
SET @pos = charindex(@delimiter, @tmpstr)
END
SET @leftover = @tmpstr
END
IF ltrim(rtrim(@leftover)) <> ''
INSERT @tbl(token) VALUES (ltrim(rtrim(@leftover)))
RETURN
END
然后您可以更改您的SP,如下所示:
CREATE PROC RupeshTest(@QueID int, @Answer varchar(250)) as
BEGIN
DECLARE @STR varchar(4000)
SELECT @STR = COALESCE(@str + ';','') + AnswerText
FROM SurveyQuestionAnswerTypes
WHERE AnswerType = (SELECT AnswerType
FROM SurveyQuestions
WHERE QuestionID = CAST(@QueId AS VARCHAR(4)))
AND AnswerValue IN (SELECT Token FROM dbo.String_To_Table(@Answer,'^'))
END
答案 1 :(得分:1)
您在这里遇到的问题是部分AnswerValue IN (2,3,5,7,8)
以及如何使其成为有效的SQL,因为这些值是整数列表,您将它们作为字符串。对我来说,一个技巧是使所有SQL命令成为一个字符串并执行它:
DECLARE @SQLQuery AS varchar(4000)
SET SQLQuery =
'SELECT AnswerText '
+ ' FROM SurveyQuestionAnswerTypes '
+ ' WHERE AnswerType = (SELECT AnswerType '
+ ' FROM SurveyQuestions '
+ ' WHERE QuestionID = ' + CAST(@QueId AS VARCHAR(4)))
+ ' AND AnswerValue IN (' + (REPLACE(@Answer,'^',',')) + ')'
EXECUTE(@SQLQuery)
顺便说一句,没有理由用^发送数字然后改变它。
答案 2 :(得分:0)
您可以用
替换最后一个条件AND CHARINDEX(CONCAT("^", CAST(AnswerValue AS CHAR), "^"), CONCAT("^", @Answer, "^"))
这似乎并不完全正确,但它可能会成功。
<强>编辑强>
感谢您的更正。