我正在尝试运行一个spring应用程序。我的web.xml看起来
<?xml version="1.0" encoding="utf-8"?>
<web-app
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>WEB-INF/beans.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<servlet>
<servlet-name>CXFServlet</servlet-name>
<servlet-class>
org.apache.cxf.transport.servlet.CXFServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CXFServlet</servlet-name>
<url-pattern>/version/2.0/*</url-pattern>
</servlet-mapping>
<filter-mapping>
<filter-name>encodingFilter</filter-name>
<url-pattern>/version/2.0/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>encodingFilter</filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>utf-8</param-value>
</init-param>
<init-param>
<param-name>forceEncoding</param-name>
<param-value>true</param-value>
</init-param>
</filter>
我收到错误
java.lang.IllegalStateException:没有名为encodingFilter的过滤器 在org.eclipse.jetty.servlet.ServletHandler.updateMappings(ServletHandler.java:1148) 在org.eclipse.jetty.servlet.ServletHandler.setFilterMappings(ServletHandler.java:1249) 在org.eclipse.jetty.servlet.ServletHandler.addFilterMapping(ServletHandler.java:1079)
我正在创建一个jetty-pkg作为jar文件并运行它 java -jar myjar.jar
答案 0 :(得分:3)
我在某处读过&lt; filter&gt;应该在&lt; filter-mapping&gt;之前创建。我交换了位置并且能够解决它..
答案 1 :(得分:0)
答案 2 :(得分:0)
只需将您的web.xml
XSD定义更新为较新版本,例如3.1
<?xml version="1.0" encoding="utf-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">