Question

我一直在使用stackoverflow来帮助我，但是现在我很难过 - 希望我能在这个问题上得到一些指导：

我有两张桌子，一张包含NFL分区，另一张包含NFL队伍。它们通过division_id字段连接（Divisions表上的主键，Teams表上的外键）。

我想要做的是在查询中加入表格并输出分组小组。我可以在PHP中使用两个单独的查询/循环完成此操作，但我想知道如何通过在单个查询中连接两个表来实现此目的。

这就是我所拥有的：

$query = "SELECT Divisions.division_id, Divisions.conference, Divisions.name, 
    Teams.name FROM Divisions INNER JOIN Teams ON 
    Teams.division_id = Divisions.division_id ORDER BY Divisions.division_id";

if( $result = $db->query($query) ){
  while( $row = $result->fetch_object() ){
    // here is where I'm stuck
  }
}

我试图让最终输出看起来类似于：

AFC North
克利夫兰布朗队匹兹堡钢人队巴尔的摩乌鸦队辛辛那提孟加拉虎

AFC East
布法罗比尔迈阿密海豚队等。

主要感谢任何可以帮助我的人！我在两年多的时间里没有做过任何编程，只是重新开始编程。

Answer 1

遍历行并在division_id更改时输出新标头：

$query = "SELECT Divisions.division_id, Divisions.conference, Divisions.name, 
    Teams.name AS teamName FROM Divisions INNER JOIN Teams ON 
    Teams.division_id = Divisions.division_id ORDER BY Divisions.division_id";

if ($result = $db->query($query)) {
    $division = "";
    while ($row = $result->fetch_object()) {
        if ($division != $row["division_id"])
        {
            $division = $row["division_id"];
            echo "<br /><h2>{$row["conference"]}</h2>";
        }

        echo "{$row["teamName"]}<br />";
    }
}

Answer 2

$result = array();
if( $result = $db->query($query) ){

  while( $row = $result->fetch_object() ){
    if(empty($result[$row['division_id']])
    {
       $result[$row['division_id']] = $row;
    }
    $result[$row['division_id']]['teams'][] = $row;
  }
}
print_r($result);

Answer 3

你可以循环检查它是否是同一个分区。如果它是一个新的部门，请写下它并<br />

$query = "SELECT Divisions.division_id, Divisions.conference, Divisions.name, 
    Teams.name as teamName FROM Divisions INNER JOIN Teams ON 
    Teams.division_id = Divisions.division_id ORDER BY Divisions.division_id";

if( $result = $db->query($query) ){
    $lastDivision = -1;
  while( $row = $result->fetch_object() ){
    if($lastDivision != $row["division_id"]){
        //here it is a new division,
        echo "<b>" . $row["division_id"] . "</b><br />";
    }else{
        //not a new division so we just continu to write teams
        echo $row["teamName"] . "<br />";
    }
    $lastDivision = $row["division_id"];
  }
}

加入两个表并迭代数据

3 个答案: