Question

我有一个绑定到我的视图模型的Listbox。此视图模型具有属性

我需要让这个项目可见，但是在更改此字段时无法点击。任何人的建议

public interface IRegionAreaDM 
{

    /// <summary>
    /// Name of the Focus Area
    /// </summary>
    string RegionAreaName { get; set; }

    /// <summary>
    /// Determines if the Tab is currently selected.
    /// </summary>
    bool IsSelected { get; set; }

    /// <summary>
    /// Determines if the Tab is linked to any other Tab
    /// </summary>
    bool IsLinked { get; set; }

    /// <summary>
    ///
    /// </summary>
    bool IsActive { get; set; }

}

每个项目都连接到XAML中的项目，例如带有文本框的名称。使用CheckBox选择IsSective，并根据逻辑使ListBoxItems启用/禁用而我的Xaml风格就像是这样的

 <Style TargetType="ListBoxItem">
      <Setter Property="Template">
        <Setter.Value>
          <ControlTemplate TargetType="ListBoxItem">
            <Border x:Name="Bd" HorizontalAlignment="Stretch" Background="#00D05252"
                    BorderThickness="0,1" SnapsToDevicePixels="true">
              <!--  <StackPanel x:Name="ParamterRoot" Orientation="Horizontal">  -->
              <Grid x:Name="ParamterRoot">
                <Grid.ColumnDefinitions>
                  <ColumnDefinition Width="Auto" />
                  <ColumnDefinition Width="*" />
                  <ColumnDefinition Width="Auto" />
                </Grid.ColumnDefinitions>
                <CheckBox x:Name="ParametersCheckbox" Grid.Column="0" Margin="10,0,0,0"
                          VerticalAlignment="Center" IsChecked="{Binding IsSelected}"
                <TextBlock Grid.Column="1" Width="Auto" Margin="20,7.5,0,7.5"
                           Text="{Binding RegionAreaName}" TextTrimming="CharacterEllipsis">
                  <TextBlock.Style>
                    <Style TargetType="{x:Type TextBlock}">
                      <Style.Triggers>
                        <Trigger Property="IsMouseDirectlyOver" Value="True">
                          <Setter Property="Cursor" Value="Hand" />
                        </Trigger>
                      </Style.Triggers>
                    </Style>
                  </TextBlock.Style>
                </TextBlock>                   
              </Grid>
              <!--  </StackPanel>  -->
            </Border>
            <ControlTemplate.Triggers>
              <Trigger Property="IsMouseOver" Value="true">
                <Setter TargetName="Bd" Property="Background" Value="#FFC10000" />
              </Trigger>
              <Trigger Property="IsSelected" Value="true">
                <Setter TargetName="Bd" Property="Background" Value="#FFC10000" />
              </Trigger>
 <DataTrigger Binding="{Binding IsActive}" Value="False">
                                    <Setter Property="IsEnabled" Value="False" />
                                </DataTrigger>

            </ControlTemplate.Triggers>
          </ControlTemplate>
        </Setter.Value>
      </Setter>
    </Style>

Answer 1

enter image description here

Code Behind :(您正在使用MVVM，因此您可以稍微调整此代码，但要适合您的模式）

public partial class Window1 : Window
{
    public List<T> Items { get; set; }
    public Window1()
    {
        Items = new List<T>
                    {
                        new T{  Id = 1,Name = "qwe",IsEnabled = true},
                        new T{  Id = 2,Name = "asd",IsEnabled = false},
                        new T{  Id = 3,Name = "zxc",IsEnabled = true},
                        new T{  Id = 4,Name = "rty",IsEnabled = false},
                    };
        InitializeComponent();            
        DataContext = this;
    }
}

public class T
{
    public int Id { get; set; }
    public String Name { get; set; }
    public bool IsEnabled { get; set; }
}

XAML：

<ListBox Name="listBox1" ItemsSource="{Binding Items}" DisplayMemberPath="Name">
    <ListBox.ItemContainerStyle>
        <Style TargetType="{x:Type ListBoxItem}">
            <Setter Property="IsEnabled" Value="{Binding IsEnabled,Mode=TwoWay}" />
        </Style>
    </ListBox.ItemContainerStyle>
</ListBox>

希望这个帮助

Answer 2

如果你想改变你的风格触发器中的某些内容，那么你必须在你的风格中设置这个属性！所以只需将默认的IsEnabled setter添加到您的样式中。

<Style TargetType="ListBoxItem">
   <Setter Property="IsEnabled" Value="True" /><!-- default -->
   ...from here your stuff

Answer 3

设置IsEnabled woudld的另一种方法是使用触发器来设置UIElement.IsHitTestVisible属性。

 <DataTrigger Binding="{Binding IsActive}" Value="False"> 
    <Setter Property="IsHitTestVisible" Value="False" /> 
 </DataTrigger>

如何使列表框中的项目可见，但不可点击

3 个答案: