我最近在这个网站上注册了，因为我真的陷入了一项任务，我需要创建一个用户输入一个月的程序，程序会显示该月的天数。用户还必须输入年份，以便程序可以检查是否是闰年，以防用户输入2月份。
这是我到目前为止所提出的编码：
def get_year():
year = raw_input("Please enter the year: ")
return year
def get_month():
month = raw_input("Please enter the month: ")
return month
def leap_year(year):
if year % 4 == 0:
return true
else:
return false
def get_days(month):
if month == "january":
print "31 days"
elif month == "february" and leap_year == true:
print "29 days"
else:
print "28 days"
if month == "march":
print "31 days"
elif month == "april":
print "30 days"
elif month == "may":
print "31 days"
elif month == "june":
print "30 days"
elif month == "july":
print "31 days"
elif month == "august":
print "31 days"
elif month == "september":
print "30 days"
elif month == "october":
print "31 days"
elif month == "november":
print "30 days"
elif month == "december":
print "31 days"
else:
print
def main():
user_year = get_year()
user_month = get_month()
leap_year(user_year)
get_days(user_month)
main()
无论如何很明显我的get_days函数中有一个错误，我只是不确定 如何编写代码，以便程序知道用户输入一个月如 一月或三月。我猜测输入必须是一个变量，因为每个 month是一个字符串，需要一个变量字符串。但我可能完全错了。
我对python很新（现在正好两个星期以及关于学校作业的编程）所以我对python编程的许多细节都不太清楚，所以如果有人能帮助我正确的方向，非常感谢！
答案 0 :(得分：0)
if-elif在二月被打破了。微小的变化是继续使用if-elif逻辑的不间断模式：
def get_days(month):
if month == "january":
print "31 days"
elif month == "february" and leap_year:
print "29 days"
elif month == "february" and not leap_year:
print "28 days"
elif month == "march":
print "31 days"
elif month == "april":
print "30 days"
elif month == "may":
print "31 days"
elif month == "june":
print "30 days"
elif month == "july":
print "31 days"
elif month == "august":
print "31 days"
elif month == "september":
print "30 days"
elif month == "october":
print "31 days"
elif month == "november":
print "30 days"
elif month == "december":
print "31 days"
else:
print 'unknown month'
答案 1 :(得分：0)
你有点亲近。我做了一些修改，我评论过。正如Raymond Hettinger指出的那样，get_days(month) 完全被打破。
def get_year():
year = raw_input("Please enter the year: ")
return int(year) #otherwise it is a string!
def get_month():
month = raw_input("Please enter the month: ")
return month
def leap_year(year):
if year % 4 == 0:
return True
else:
return False
def get_days(month,leap_year): #leap_year must be passes to this function
#This checks for "january" and "february" with leap years
#and falls back to last option on EVERYTHING ELSE like a feb without a leap year or even a "march"
if month == "january":
print "31 days"
elif month == "february" and leap_year == True:
print "29 days"
else:
print "28 days"
#this is a separate block that runs AFTER the previous block
if month == "march":
print "31 days"
elif month == "april":
print "30 days"
elif month == "may":
print "31 days"
elif month == "june":
print "30 days"
elif month == "july":
print "31 days"
elif month == "august":
print "31 days"
elif month == "september":
print "30 days"
elif month == "october":
print "31 days"
elif month == "november":
print "30 days"
elif month == "december":
print "31 days"
else:
print "invalid input" #so that it doesnt fail silently when I enter 2
def main():
user_year = get_year()
user_month = get_month()
leap_status = leap_year(user_year) #store the leap_year status to a variable
get_days(user_month, leap_status) #and then pass it to a function
main()
答案 2 :(得分：0)
我建议你使用python中内置数据类型的字典。
def get_days(year, month):
"""
take year and month ,return the days in that month.
"""
#define a dictionary and the month is key which value is days
daydict = dict()
daydict = ['january'=31, 'february'=28, 'februaryinleapyear'=29,
'march'=31, 'april'=30,
'may'=31, 'june'=30,
'july'=31, 'august'=31,
'september'=30, 'october'=31,
'november'=30, 'december'=31 ]
try:
if month in daydict:
if month == 'february' and leap_year(year):
print daydict[februaryinleapyear]
else:
print daydict[month]
else:
print 'The year or month you input is invalid !'
except:
print 'error!'
答案 3 :(得分：0)
n=int(input('enter no of days in a month= '))
#0=sunday
#1=moday
#2=tuesday
#3=wednesday
#4=thursday
#5=friday
#6=saturday
d=int(input('enter the starting day of month= '))
print('sun','mon','tue','wed','thu','fri','sat',sep='\t')
for j in range(d):
print (' ',end='\t')
i=1
while(i<=n):
print (i,end='\t')
if(i+d)%7==0:
print('\t')
i=i+1
答案 4 :(得分：0)
此代码询问用户输入（more simple codes）
#python calendar days in month.
month= input ("Enter the month('January', ...,'December'): ") # ask for inputs from user
start=input ("Enter the start day ('Monday', ..., 'Sunday'): ")
if start== "Monday" :
num=1
elif start== "Tuesday" :
num=0
elif start== "Wednesday" :
num=-1
elif start== "Thursday" :
num=-2
elif start== "Friday" :
num=-3
elif start== "Sartday" :
num=-4
elif start=="Sunday":
num=-5
print(month)
print("Mo Tu We Th Fr Sa Su") #the header of the Calender
if month== "January" or month=="March" or month=="May" or month=="July" or month=="August" or month=="October" or month=="December" :
#for month with 31 days
for num_ in range (num,num+41,7):
for i in range(7):
if num<1:
print (' ',end="")
elif num>31:
print("",end="")
else:
print ("{0:>2}".format(num),end="")
if i<6 and num<31:
print(" ",end="")
num +=1
print()
elif month== "April" or month=="June" or month=="Septemmber" or month=="November":
#for month with 30 days
for num_ in range (num,num+41,7):
for i in range(7):
if num<1:
print (' ',end="")
elif num>30:
print("",end="")
else:
print ("{0:>2}".format(num),end="")
if i<6 and num<30:
print(" ",end="")
num +=1
print()
elif month== "February" :
# february is an exception : it has 28 days
for num_ in range (num,num+41,7):
for i in range(7):
if num<1:
print (' ',end="")
elif num>28:
print("",end="")
else:
print ("{0:>2}".format(num),end="")
if i<6 and num<28:
print(" ",end="")
num +=1
print()
else:
print("invalid entry")