如何在LINQ中执行此操作?
select
*
from customer c
left join order o on o.CustomerID = c.CustomerID
where o.OrderDate = (select MAX(OrderDate) from order where CustomerID = o.CustomerID )
不担心重复,因为每天只会有一个订单。
我得到了LINQ中的左连接,但不确定子查询的放置方式和位置。
var query = from customer in clist
from order in olist
.Where(o => o.CustomerID == customer.CustomerID)
select new {
customer.CustomerID,
customer.Name,
customer.Address,
Product = order != null ? order.Product : string.Empty
};
最终解决方案:
var query = from customer in clist
from order in olist
.Where(o => o.CustomerID == customer.CustomerID && o.OrderDate ==
olist.Where(o1 => o1.CustomerID == customer.CustomerID).Max(o1 => o1.OrderDate)
)
select new {
customer.CustomerID,
customer.Name,
customer.Address,
order.Product,
order.OrderDate
};
没有任何lambdas的另一种解决方案
var query = from customer in clist
from order in olist
where order.CustomerID == customer.CustomerID && order.OrderDate ==
(from o in olist
where o.CustomerID == customer.CustomerID
select o.OrderDate).Max()
select new {
customer.CustomerID,
customer.Name,
customer.Address,
order.Product,
order.OrderDate
};
答案 0 :(得分:15)
这或多或少是字面翻译
var query = from customer in clist
from order in olist
.Where(o => o.CustomerID == customer.CustomerID &&
o.OrderDate == olist
.Where(o => o.CustomerID == customer.CustomerID)
.Select(o => o.OrderDate).Max())
select new {
customer.CustomerID,
customer.Name,
customer.Address,
Product = order != null ? order.Product : string.Empty
};
但我会重写
var query = from customer in clist
from order in olist
.Where(o => o.CustomerID == customer.CustomerID)
.OrderByDescending(o => o.OrderDate).Take(1)
select new {
customer.CustomerID,
customer.Name,
customer.Address,
Product = order != null ? order.Product : string.Empty
};
答案 1 :(得分:1)
这对你有什么用?
var query =
from customer in clist
join order in olist
on customer.CustomerID equals order.CustomerID
into orders
select new
{
customer.CustomerID,
customer.Name,
customer.Address,
Product = orders
.OrderByDescending(x => x.OrderDate)
.Select(x => x.Product)
.FirstOrDefault() ?? String.Empty
};