mysql查询，给我错误的行数

Question

我正在尝试创建搜索页面，这是我的查询。我有3张桌子，“服务”，“收视率”和“商店”。 '商店'包含88个结果，而'评级'包含93，当使用时：        $ nr = mysql_num_rows（$ result）; 它返回了93，而不是像我预期的那样88，如何归还88家商店，它实际上是对于超过1个评级的商店的结果加倍。例如：如果商店有2票，商店会出现两次。

    $result = mysql_query("SELECT services.*, ratings.*, shops.*, temp.total as final_total, 
CONCAT(shop_number, ' ', shop_location, ' ', shop_city, ' ', shop_province, ' ', shop_postcode) AS address FROM shops

inner join services on shops.shop_id=services.shop_id   
inner join ratings on shops.shop_id=ratings.shop_id
inner join (select SUM(comfort + service + ambience + friendliness)/(12) / COUNT(shop_id) AS total, shop_id FROM ratings GROUP BY shop_id ) as temp on shops.shop_id=temp.shop_id 
    HAVING temp.total >= '$search_total_rating'

    AND address LIKE '%$search_shop_address%' 
    AND shop_name LIKE '%$search_shop_name%'
    AND comfort >= '$search_shop_comfort' 
    AND service >= '$search_shop_service' 
    AND ambience >= '$search_shop_ambience' 
    AND friendliness >= '$search_shop_friendliness'
         ORDER BY shop_name ASC");