Question

我有一个JS脚本，我将代码转换为PHP，但我仍然坚持使用正确的语法来创建与PHP脚本中的这段代码相同的代码：

var sdata = {
           "13":{
               "22":["618","22","1","1","0","0","0"],
               "21":["617","22","1","1","0","0","0"]
           },               
           "14":{
                "22":["619","22","1","1","0","0","0"],
                "20":["622","22","1","1","0","0","0"]
           },    
           "15":{
                "20":["623","22","1","1","0","0","0"]
     }
};

有什么想法吗？

Answer 1

最简单的做法是确保你的确切是使用jQuery .get函数，将此数组作为数据的一部分发送，然后在$ _GET变量上运行PHP函数json_decode以获取PHP array :)如果你需要对它进行硬编码，你可以print_r数组。

Answer 2

$sdata = array(
           "13" => array(
               "22" => array("618","22","1","1","0","0","0"),
               "21" => array("617","22","1","1","0","0","0")
           ),               
           "14" => array(
                "22" => array("619","22","1","1","0","0","0"),
                "20" => array("622","22","1","1","0","0","0")
           ),    
           "15" => array(
                "20" => array("623","22","1","1","0","0","0")
     )
);

Answer 3

签出多维数组：

http://php.net/manual/en/language.types.array.php

Answer 4

看起来你需要的是一个多维数组。由于您似乎是PHP的新手，请查看PHP中阵列手册页上的代码示例： http://php.net/manual/en/language.types.array.php

用于设置变量的PHP语法

4 个答案: